The value of x such that f(x) = g(x) is x = 3
<h3>Quadratic equation</h3>
Given the following expressions as shown
f(x) = x^3-3x^2+2 and;
g(x) = x^2 -6x+11
Equate the expressions
x^3-3x^2+2 = x^2 -6x+11
Equate to zero
x^3-3x^2-x^2+2-11 = 0
x^3-3x^2-x^2 + 6x - 9 = 0
x^3-4x^2+6x-9 = 0
Factorize
On factorizing the value of x = 3
Hence the value of x such that f(x) = g(x) is x = 3
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Answer:
BC = 24
Step-by-step explanation:
FD = 36, FE = 15 and CD = 18
By secant theorem.
DE • DF = CD • DB
(36 - 15) • 36 = 18 • DB
DB = 42
BC = DB - CD
BC = 42 - 18
BC = 24
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First isolate the x. Always remember that the way you do this is the opposite of the what is happening to the number you want to move.
You want to move the -5 from the left side to the right side by doing the opposite and adding it to both sides.
Like: 27x-5=-5+11
27x-5+5=11+5
So 27x=11 Continue to isolate the variable
Converting all to mixed number form the choices are;
-0.75, 0.5, 0.6, -2.3, and 1.2
Now we can list them from least to greatest:
-7/3, -3/4, 0.5, 2/3, and 1.2
You could make a total of 10 scarves
10/4=2.5
25/2.5=10