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3 years ago

Aaron has two apple's. He adds two more apples. How much apple's does Aaron has now

Mathematics

2 answers:

Pavlova-9 [17]3 years ago

5 0

Answer:

Aaron has 4 apples now.

Step-by-step explanation:

Well it says he already has two apple's

And that he add two more apple's

So if that is true we have to use addition to solve this

2+2=4

So Aaron has 4 apples

lorasvet [3.4K]3 years ago

4 0

Aaron has 4 apples. 2+2=4

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Pls help meeeeee<br><br> what is 9+10

elena-s [515]

Answer:

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

What is the difference?

Serhud [2]

Answer:

The option $\frac{(x+5)(x+2)}{x^3-9x}$ is correct

The difference of the given expression is

$\frac{2x+5}{x^2-3x}-(\frac{3x+5}{x^3-9x})-({\frac{x+1}{x^2-9})=\frac{(x+5)(x+2)}{x^3-9x}$

Step-by-step explanation:

Given expression is $\frac{2x+5}{x^2-3x}-(\frac{3x+5}{x^3-9x})-({\frac{x+1}{x^2-9})$

To find the difference of the given expression as below :

$\frac{2x+5}{x^2-3x}-(\frac{3x+5}{x^3-9x})-({\frac{x+1}{x^2-9})$

$=\frac{2x+5}{x(x-3)}-(\frac{3x+5}{x(x^2-9)})-({\frac{x+1}{x^2-9})$

$=\frac{2x+5}{x(x-3)}-(\frac{3x+5}{x(x^2-3^2)})-({\frac{x+1}{x^2-3^2})$

$=\frac{2x+5}{x(x-3)}-(\frac{3x+5}{x(x-3)(x+3)})-({\frac{x+1}{(x-3)(x+3)})$

( using the formula $a^2-b^2=(a+b)(a-b)$ )

$=\frac{2x+5(x+3)-(3x+5)-x(x+1)}{x(x-3)(x+3)}$

$=\frac{2x^2+6x+5x+15-3x-5-x^2-x}{x(x-3)(x+3)}$ (adding the like terms)

$=\frac{x^2+7x+10}{x(x^2-9)}$ ( by factoring the quadratic polynomial )

$=\frac{(x+5)(x+2)}{x^3-9x}$

Therefore $\frac{2x+5}{x^2-3x}-(\frac{3x+5}{x^3-9x})-({\frac{x+1}{x^2-9})=\frac{(x+5)(x+2)}{x^3-9x}$

Therefore the difference of the given expression is

$\frac{(x+5)(x+2)}{x^3-9x}$

Therefore option $\frac{(x+5)(x+2)}{x^3-9x}$ is correct

8 0

3 years ago

The cost of a ticket to a Circus & Fan Fair show is $69 for adults and $26 for children. On a

Vlada [557]

Let the number of adults equal x, and the number of children equal 5x.

26(5x) + 69x = 94908

194x = 94908

x = approx. 489

About 489 adults bought tickets.

7 0

3 years ago

Misha Larkins [42]

Answer: $2x^{2} + 5x -3$

Step-by-step explanation:

Find the quotient of $\frac{16x^4+40x^3-24x^2}{8x^2}$

Step 1: Break down the polynomial equation

$\frac{16x^4}{8x^2}$ + $\frac{40x^3}{8x^2}$ - $\frac{24x^2}{8x^2}$

Step 2: Divide each piece by dividing the coeffients and subtracting the variables.

16 ÷ 8 = 2

$x^{4}$ - $x^{2}$ = $x^{2}$ → 2 $x^{2}$

40 ÷ 8 = 5

$x^{3}$ - $x^{2}$ = $x$ → 5 $x$

- 24 ÷ 8 = - 3

$x^{2}$ - $x^{2}$ = 1 → - 3

Step 3: Put the polynomial together

2 $x^{2}$ + 5 $x$ - 3

3 0

3 years ago

If length and width of a rectangle are in the ratio 4 to 5 and the perimeter of the rectangle is 144, find the dimensions of the

beks73 [17]

144/2=72
72/9=8
8×4=32
8×5=40
therefore 32 and 40

6 0

4 years ago