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2 years ago

HELP

Mathematics

1 answer:

Solnce55 [7]2 years ago

3 0

12,989 is the answer i believe

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Complete the sequence: 1, 1, 2, 3, 5, ____, ____, ____.

Elza [17]

Answer:

8, 13, 21

Step-by-step explanation:

This is a part of the Fibonacci sequence. it is where you add the two previous numbers together to get the third.

Ex.

1+1 = 2

1+2 = 3

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3 years ago

An isosceles triangle has two angles both equal to x°. The third angle is 60° bigger than either of these. Find the value of x°.

Elina [12.6K]

X+x+(x+60)=180
3x+60=180
3x=120
x=40

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3 years ago

How do you calculate the population mean

bazaltina [42]

Add up all the numbers then divide how many ever digits there are

7 0

3 years ago

This is the last question need answered so please help me

shusha [124]

Assuming that is a square pyramid

that is the square base+4 triangles
that is
side^2+4(1/2bh)
where b=side=14in
and h=height=13in

surface area=14^2+4(1/2)(14)(13)
SA=196+(2)(182)
SA=196+364
SA=560 square inches

6 0

2 years ago

cylinder shaped can needs to be constructed to hold 200 cubic centimeters of soup. The material for the sides of the can costs 0

Dafna11 [192]

Answer:

Radius=2.09 cm

Height,h=14.57 cm

Step-by-step explanation:

We are given that

Volume of cylinderical shaped can=200 cubic cm.

Cost of sides of can=0.02 cents per square cm

Cost of top and bottom of the can =0.07 cents per square cm

Curved surface area of cylinder= $2\pi rh$

Area of circular base=Area of circular top= $\pi r^2$

Total cost,C(r)= $0.02\times 2\pi rh+2\pi r^2\times 0.07$

Volume of cylinder, $V=\pi r^2 h$

$200=\pi r^2 h$

$h=\frac{200}{\pi r^2}$

Substitute the value of h

$C(r)=0.02\times 2\pi r\times \frac{200}{\pi r^2}+2\pi r^2\times 0.07$

$C(r)=\frac{8}{r}+0.14\pi r^2$

Differentiate w.r.t r

$C'(r)=-\frac{8}{r^2}+0.28\pi r$

$C'(r)=0$

$-\frac{8}{r^2}+0.28\pi r=0$

$0.28\pi r=\frac{8}{r^2}$

$r^3=\frac{8}{0.28\pi}=9.095$

$r=(9.095)^{\frac{1}{3}}=2.09$

Again, differentiate w.r.t r

$C''(r)=\frac{16}{r^3}+0.28\pi$

Substitute the value of r

$C''(2.09)=\frac{16}{(2.09)^3}+0.28\pi=2.63>0$

Therefore,the product cost is minimum at r=2.09

h= $\frac{200}{\pi (2.09)^2}=14.57$

Radius of can,r=2.09 cm

Height of cone,h=14.57 cm

4 0

3 years ago