All categories

3 years ago

WILL MARK BRAINLIEST!!

Mathematics

1 answer:

Nezavi [6.7K]3 years ago

7 0

Answer:

Wait..Where's the question?

Step-by-step explanation:

You might be interested in

For the past 5 months, Marissa recorded the change in dollar amount on her electric bill. per month.

leonid [27]

Answer:

18.02+1.03=19.05

19.05-0.44=18.61

18.61-0.84=17.77

17.77-1.19=16.58

3 0

4 years ago

Read 2 more answers

Joe borrowed $8,000 from the bank at a rate of 7% simple interest per year. How much interest did he pay in 9 years?

AleksAgata [21]

Answer:

5,040.00

Step-by-step explanation:

First, converting R percent to r a decimal

r = R/100 = 7%/100 = 0.07 per year.

Solving our equation:

A = 8000(1 + (0.07 × 9)) = 13040

A = $13,040.00

The total amount accrued, principal plus interest, from simple interest on a principal of $8,000.00 at a rate of 7% per year for 9 years is $13,040.00.

3 0

3 years ago

3/4w - 1 / 2w - 4 = 12

Rasek [7]

The answer to this problem is w=64,

7 0

3 years ago

Read 2 more answers

PLEASE HELP FAST! my problem is in the photo.

Xelga [282]

[c] 70°

40+2x=180
2x=140
x=70

i use 2x since the angle measures of D and C are equivalent since it is an isosceles

7 0

3 years ago

"You are dating Moon rocks based on their proportions of uranium-238 (half-life of about 4.5 billion years) and its ultimate dec

Olenka [21]

Step-by-step explanation:

Initial mass of the isotope = x

Time taken by the sample to decay its mass by 41% = t

Formula used :

$N=N_o\times e^{-\lambda t}\\\\\lambda =\frac{0.693}{t_{\frac{1}{2}}}$

where,

$N_o$ = initial mass of isotope = x

N = mass of the parent isotope left after the time, (t) = 59% of x = 0.59x

$t_{\frac{1}{2}}$ = half life of the isotope = 4.5 billion years

$\lambda$ = rate constant

Now put all the given values in this formula, we get

$0.59x=x\times e^{-(\frac{0.693}{\text{4.5 billion years}})\times t}$

t = 3.4 billion years

The age a rock is 3.4 billion years.

Initial mass of the isotope = x

Time taken by the sample to decay its mass by 35%= t

Formula used :

$N=N_o\times e^{-\lambda t}\\\\\lambda =\frac{0.693}{t_{\frac{1}{2}}}$

where,

$N_o$ = initial mass of isotope = x

N = mass of the parent isotope left after the time, (t) = 65% of x = 0.65x

$t_{\frac{1}{2}}$ = half life of the isotope = 4.5 billion years

$\lambda$ = rate constant

Now put all the given values in this formula, we get

$0.65x=x\times e^{-(\frac{0.693}{\text{4.5 billion years}})\times t}$

t = 2.8 billion years

The age a rock is 2.8 billion years.

5 0

4 years ago