Ask question

Ask question

All categories

3 years ago

14

3/4w - 1 / 2w - 4 = 12

2 answers:

Rasek [7]3 years ago

7 0

The answer to this problem is w=64,

Liula [17]3 years ago

4 0

Given equation) 3/4w- 1/2w- 4= 12
Step 1) 1/4w-4=12 (combining like terms)
Step 2) 1/4w= 16 (adding 4 to both sides)
Step 3) w= 4 (divide what is attached to the variable)

You might be interested in

8) Find the are of the rregular shape.<br> 3 ft.<br> 3 ft.<br> 6 ft.<br> 9 ft.<br> 6 ft.<br> 9 ft.

kykrilka [37]

Answer:

63 ft squared

Step-by-step explanation:

3x3=9 for top square

9*6=54 for bottom one

54+9=63

3 0

3 years ago

Read 2 more answers

Suppose the graph of a cubic polynomial function

ivann1987 [24]

Answer:

(1/6)(x-2)(x-3)(x-5)

Step-by-step explanation:

7 0

3 years ago

Determine formula of the nth term 2, 6, 12 20 30,42

nalin [4]

Check the forward differences of the sequence.

If $\{a_n\} = \{2,6,12,20,30,42,\ldots\}$ , then let $\{b_n\}$ be the sequence of first-order differences of $\{a_n\}$ . That is, for n ≥ 1,

$b_n = a_{n+1} - a_n$

so that $\{b_n\} = \{4, 6, 8, 10, 12, \ldots\}$ .

Let $\{c_n\}$ be the sequence of differences of $\{b_n\}$ ,

$c_n = b_{n+1} - b_n$

and we see that this is a constant sequence, $\{c_n\} = \{2, 2, 2, 2, \ldots\}$ . In other words, $\{b_n\}$ is an arithmetic sequence with common difference between terms of 2. That is,

$2 = b_{n+1} - b_n \implies b_{n+1} = b_n + 2$

and we can solve for $b_n$ in terms of $b_1=4$ :

$b_{n+1} = b_n + 2$

$b_{n+1} = (b_{n-1}+2) + 2 = b_{n-1} + 2\times2$

$b_{n+1} = (b_{n-2}+2) + 2\times2 = b_{n-2} + 3\times2$

and so on down to

$b_{n+1} = b_1 + 2n \implies b_{n+1} = 2n + 4 \implies b_n = 2(n-1)+4 = 2(n + 1)$

We solve for $a_n$ in the same way.

$2(n+1) = a_{n+1} - a_n \implies a_{n+1} = a_n + 2(n + 1)$

Then

$a_{n+1} = (a_{n-1} + 2n) + 2(n+1) \\ ~~~~~~~= a_{n-1} + 2 ((n+1) + n)$

$a_{n+1} = (a_{n-2} + 2(n-1)) + 2((n+1)+n) \\ ~~~~~~~ = a_{n-2} + 2 ((n+1) + n + (n-1))$

$a_{n+1} = (a_{n-3} + 2(n-2)) + 2((n+1)+n+(n-1)) \\ ~~~~~~~= a_{n-3} + 2 ((n+1) + n + (n-1) + (n-2))$

and so on down to

$a_{n+1} = a_1 + 2 \displaystyle \sum_{k=2}^{n+1} k = 2 + 2 \times \frac{n(n+3)}2$

$\implies a_{n+1} = n^2 + 3n + 2 \implies \boxed{a_n = n^2 + n}$

6 0

2 years ago

Tim deposit 4500 in a savings account that pays 4.5% simple interest. How much interest does she earn into years?

sertanlavr [38]

Answer:

ummmm is it meant to ask in 2 years instead of into years? if so

5 0

3 years ago

the electric bill in may was $248.00 in june the bill was $265.00 what is the percent of increase rounded to the nearest hundred

lions [1.4K]

265-248=17
(17/248)x100=6.854838
round that to the nearest hundredth is 6.85%
which is a

5 0

3 years ago