Ask question

Ask question

All categories

3 years ago

14

What is the solution to the equation below? Enter the answer in the format p=#, keep your answer as a fraction if necessary. -2/

3p + 1/6 = 7/10

1 answer:

Scorpion4ik [409]3 years ago

6 0

Let's solve your equation step-by-step.

-2/3p+ 1/6= 7/10

Answer:

p= -4/5

You might be interested in

I DONT GET THISS help

Ivan

The slope is the coefficient of the variable. In this case, -1/4 is before the x. So the answer is C

3 0

3 years ago

Why is 21 sqrt root an irrational number?

STatiana [176]

Answer:

Because it cannot be written as a fraction

Step-by-step explanation:

The square root of any non-perfect square will always be irrational and cannot be written as a fraction. The sqrt(21) has no repeating digits because its digits go on forever.

6 0

3 years ago

If h(x) = -2x – 10, find h(-4).<br> -2<br> -18<br> -3<br> -16

Furkat [3]

Answer:

-2

Step-by-step explanation:

replace x with -4 in the h(x) function

h(x) = -2x-10 ➡ h(-4) = (-2)×(-4)-10 ➡8-10 = -2

5 0

3 years ago

Read 2 more answers

Perform the multiplication, (7x2+a2)(x2–3a2)

aksik [14]

Answer:

The given multiplied expression is

$(7x^2+a^2)(x^2-3a^2)=7x^4-20x^2a^2-3a^4$

Step-by-step explanation:

Given expression is $(7x^2+a^2)(x^2-3a^2)$

To find the multiplication of the given expression :

$(7x^2+a^2)(x^2-3a^2)$

By using the distributive property to solve the given expression as below

$(7x^2+a^2)(x^2-3a^2)=(7x^2)(x^2)+(7x^2)(-3a^2)+(a^2)(x^2)+(a^2)(-3a^2)$

$=7x^2.x^2-21x^2a^2+a^2x^2-3a^2.a^2$

$=7x^{2+2}-21x^2a^2+a^2x^2-3a^{2+2}$ ( by using the property $a^m.a^n=a^{m+n}$ )

$=7x^4-21x^2a^2+a^2x^2-3a^4$

Adding the like terms in the above expression we get

$=7x^4-20x^2a^2-3a^4$

Therefore $(7x^2+a^2)(x^2-3a^2)=7x^4-20x^2a^2-3a^4$

Therefore the given multiplied expression is

$(7x^2+a^2)(x^2-3a^2)=7x^4-20x^2a^2-3a^4$

8 0

4 years ago

Find the greatest possible number of consecutive zeros at the end of the product of three positive integers if the sum of these

Vesnalui [34]

Answer:

I think its 5 consecutive zeros.

Step-by-step explanation:

This would be a guess but I think you would need two numbers in the hundreds that also have 2 parts of which have a product of a number ending in 0, like 4 and 5.

So my guess would be

400 * 500 * 39

= 7800000

7 0

2 years ago