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4 years ago

PLEASE HELP ME I DON'T KNOW HOW TO DO THIS

1 answer:

azamat4 years ago

8 0

Area of each lateral area = 1/2 * 14* 15
Total lateral area ( as it has 3 lateral sides) = 3 * 1/2 * 14 * 15 = 315 cm^2

Total surface area = 315 * 1/2 * 14 * 15 = 420 cm^2

Hexagonal pyramid

Lateral area = 6 * area of each triangle = 6 * 1/2 *10 * 35 = 1050 cm^2

Total S A = 1050 + area of the hexagonal base = 1050 + 3 sqrt3 10^2 / 2
= 1050 + 259.8 = 1309.8 cm^2

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Solve using the Quadratic Formula:

Advocard [28]

A. - 7x² + 7x + 1 + 8 = 0

- 7x² + 7x + 9 = 0

x = - b ± √b² - 4ac / 2a

= - 7 ± √7² - 4 (-7) (9) / 2 (-7)

= - 7 ± √49 + 252 / - 14

= - 7 ± √ 301 / - 14

x = - 7 + 17.349 / - 14 x = - 7 - 17.349 / - 14

= 10.349 / - 14 = - 24.349 / - 14

= - 0.739 = - 1.739

B. 8x² - 5x² + 6x + 1 = 0

3x² + 6x + 1 = 0

x = - b ± √b² - 4ac / 2a

= - (-5) ± √-5² - 4 (3) (1) / 2 (3)

= 5 ± √25 - 12 / 6

= 5 ± √ 13 / 6

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= 8.606/6 = - 8.606/6

= 1.434. = - 1.434

please re-check the answers hope this helps

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2 years ago

ZB = Round your answer to the nearest hundredth. C A 7 ? B

Digiron [165]

Answer: What?

Step-by-step explanation:

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3 years ago

If f(x)=2x and g(x)=x^{2}-1, which statement is true?

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4 years ago

Slope intercept form of points 0, -4 and -1, 4

slava [35]

Answer:

$y=\frac{0}{-1} -4$

Step-by-step explanation:

first, you have to find the slope, and to do that you use this equation $\frac{y2-y1}{x2-x1}$

so, now to insert your points (0,-4), (-1,4)

(x1,y1) (x2,y2)

$\frac{4-4}{-1-0} = \frac{0}{-1}$

now that you have the slope you can find the y-intercept of the slope-intercept form by looking at your first point (0,-4) and get -4

- if you were to look at this point on a graph it would be on the y-axis therefore, -4 is the y-intercept [if you don't have a point like this one then you can look at a graph with one of your points and make a slope until you are on the y-axis :)]

therefore, the slope-intercept form is y= $\frac{0}{-1}$ -4

[ps, your slope is a zero slope :)]

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hichkok12 [17]

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