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Serggg [28]
2 years ago
7

Given the graph of g(x), which is a transformation of f(x)=|x|, write the equation for g(x).

Mathematics
1 answer:
Mariulka [41]2 years ago
3 0

Step-by-step explanation:

g(x) = -f(x+1) + 2

f(x) is first reflected across the x-axis and then translated 1 unit to the left and 2 units up.

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Write an equation for the line that passes through (2, -2) and (4, -1)​
Dahasolnce [82]

Answer:  y=1/2x-3

Step-by-step explanation:

Slope-intercept form:y=mx+b

m=y2-y1/x2-x1

-1-(-2)/4-2=1/2

y=1/2x+b

-1=1/2(4)+b

-1=2+b

b=-3

6 0
3 years ago
I NEED THIS ANSWERED AS SOON AS POSSIBLE PLEASE!!
Paul [167]
The answer would be D. This is because in order to get W you would have to multiply 24 by the age (X) and add 8
4 0
3 years ago
A young female lion was brought into the wildlife zoo weighing 53.5 pounds. After two years, she weighed 5.5 times
Lera25 [3.4K]

Answer:

324

Step-by-step explanation:

This is because when rounding you multiply 55 by 6 that is equal to 330 which is near 324. However if you want the answer spot on it would be 294

3 0
2 years ago
Read 2 more answers
Simplify the expression (6x^3/3x^4)^2<br> A. 12x^5/6x^6<br> B. 4/x^2<br> C. 2x^6/x^8<br> D. 2/x
Bess [88]
The Answer is B.
Sol: (6/3x^(3-4))^2
= (2/x)^2
=4/x^2


8 0
2 years ago
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Urve revolves around the x-axis. if you cannot evaluate the integral exactly, use your calculator to approximate it. (round your
Archy [21]

The value of integration of y=16-x^{2} from x=-1 to x=1 is 94/3.

Given the equation y=16-x^{2} and the limit of the integral be x=-1,x=1.

We are required to find the value of integration of y=16-x^{2} from x=-1 to x=1.

Equation is relationship between two or more variables that are expressed in equal to form.Equation of two variables look like ax+by=c.It may be linear equation, quadratic equation, or many more depending on the power of variable.

Integration is basically opposite of differentiation.

y=16-x^{2}

Find the integration of 16-x^{2}.

=16x-x^{3}/3

Now find the value of integration from x=-1 to x=1.

=16(1)-(1)^{3}/3-16(-1)-(-1)^{3}/3

=16(1)-1/3+16-1/3

=32-2/3

=(96-2)/3

=94/3

Hence the value of integration of y=16-x^{2} from x=-1 to x=1 is 94/3.

Learn more about integration at brainly.com/question/27419605

#SPJ4

4 0
1 year ago
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