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Tom [10]
2 years ago
5

What is the volume of the sphere shown below? 13 A. 527 units O B. 676 3 i units 3 C. 8788 3 i units 3 O D. 10472 units3​

Mathematics
1 answer:
vichka [17]2 years ago
6 0
527, because it is hope it helps
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If 6x - 3y = -12 and 2x + 2y = -10, then y =
ahrayia [7]

Answer:

y=5

Step-by-step explanation:

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2 years ago
When a distribution is mound-shaped symmetrical, what is the general relationship among the values of the mean, median, and mode
yuradex [85]

Answer:

The mean, median, and mode are approximately equal.

Step-by-step explanation:

The mean, median, and mode are <em>central tendency measures</em> in a distribution. That is, they are measures that correspond to a value that represents, roughly speaking, "the center" of the data distribution.

In the case of a <em>normal distribution</em>, these measures are located at the same point (i.e., mean = median = mode) and the values for this type of distribution are symmetrically distributed above and below the mean (mean = median = mode).

When a <em>distribution is not symmetrical</em>, we say it is <em>skewed</em>. The skewness is a measure of the <em>asymmetry</em> of the distribution. In this case, <em>the mean, median and mode are not the same</em>, and we have different possibilities as the mentioned in the question: the mean is less than the median and the mode (<em>negative skew</em>), or greater than them (<em>positive skew</em>), or approximately equal than the median but much greater than the mode (a variation of a <em>positive skew</em> case).  

In the case of the normal distribution, the skewness is 0 (zero).

Therefore, in the case of a <em>mound-shaped symmetrical distribution</em>, it resembles the <em>normal distribution</em> and, as a result, it has similar characteristics for the mean, the median, and the mode, that is, <em>they are all approximately equal</em>. So, <em>the </em><em>general</em><em> relationship among the values for these central tendency measures is that they are all approximately equal for mound-shaped symmetrical distributions, </em>considering they have similar characteristics of the <em>normal distribution</em>, which is also a mound-shaped symmetrical distribution (as well as the t-student distribution).

5 0
2 years ago
If 2+2=4 what does 16m times 500m is
Karo-lina-s [1.5K]
16m times 500m = 8000m^2
3 0
3 years ago
Read 2 more answers
A student earns $11.75 per hour for gardening. if she worked 21 hours this month, then how much did she earn? show work​
ankoles [38]

Answer:

$246.75

Step-by-step explanation:

A student earns $11.75 for 1 hour

If she works for 21 hours this month then the total amount earned can be calculated as follows

= 11.75 × 21

= 246.75

Hence the total amount earned this month is $246.75

4 0
2 years ago
I need help please! ​
Sophie [7]

Answer/Step-by-step explanation:

Area of trapezium = ½*(AD + BC)*AB

Area = 42 cm²

AD = (x + 8) cm

BC = (x + 5) cm

AB = x cm

Plug in the values into the equation

42 = ½((x + 8) + (x + 5))*x

42 = ½((x + 8 + x + 5)*x

42 = ½(2x + 13)*x

Multiply both sides by 2

42*2 = (2x + 13)*x

84 = 2x² + 13x

2x² + 13x = 84

Subtract both sides by 84

2x² + 13x - 84 = 0

4 0
2 years ago
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