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statuscvo [17]
4 years ago
11

The diagram is a straightedge and compass construction. A is the center of one circle, and B is the center of the

Mathematics
1 answer:
aev [14]4 years ago
5 0

Answer:

Step-by-step explanation:

From the picture attached,

Two circles having centers A and B intersect each other at C and D.

We do a construction by joining points A and B to form a line segments AB.

From circle A,

AC ≅ AB ≅ AD [Radii of the circle A]

From circle B,

BC ≅ AB ≅ BD [Radii of the circle B]

Therefore, AC ≅ AD ≅ BC ≅ BD ≅ AB.

These segments of the quadrilateral are equal in measure.

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The width of each of five continuous classes in a frequency distribution is 5 and the lower class-limit of the lowest class is 1
Helga [31]

Let x and y be the upper and lower class limit of frequency distribution.

Given, width of the class = 5

⇒ x-y= 5 …

Also, given lower class (y) = 10 On putting y = 10, we get

x – 10= 5 ⇒ x = 15 So, the upper class limit of the lowest class is 15

Hence, the upper class limit of the highest class

=(Number of continuous classes x Class width + Lower class limit of the lowest class)

= 5 x 5+10 = 25+10=35

Hence,’the upper class limit of the highest class is 35.

<em><u>Alternate Method</u></em><em><u>.</u></em>

After finding the upper class limit of the lowest class, the five continuous classes in a frequency distribution with width 5 are 10-15,15-20, 20-25, 25-30 and 30-35.

Thus, the highest class is 30-35..

<h3>Hence, the upper limit of this class is 35.</h3>

<h2>_____________________</h2>

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3 years ago
Angle 4 above has a measurement of 160 degrees. Angle 1 has a label
Elena-2011 [213]

Answer: A

Step-by-step explanation:

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Answer:

Hi,

Step-by-step explanation:

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Step-by-step explanation:

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5% of the strawberries.
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