Lets check the first point (0,6)
3*0+4=4 no good
0+6 =6 good
0^2+6 =6 good
6 * (7/6) ^0 =6 good
Lets check the second point (1,7)
3*1+4= we don't care since it didn't work for (0,6)
1+6 =7
1^2+6 =7
6 * (7/6) ^1 =7
Lets check the third point (2,10)
3x+4= we still don't care
2+6 = 8 no good
2^2+6 =10 good
6 * (7/6) ^2 =6 * 49/36 =49/6 no good
f(x) = x^2 +6
Uh I’m not even gonna question it but thanks for the free points ig? Lol
K<4
that should be the answer to your question
Answer:
Q' (-3,4)
Step-by-step explanation:
A reflection across the x-axis would mean that only the x value of the point would change. This means that the y value would still be 4. To find the x value, just flip it to a negative. The negative of 3 is -3
