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fenix001 [56]
3 years ago
10

Neon is a completely stable gas and will not react with other elements. Which of the following elements will react similarly to

Neon?
A. Xenon because it has the same number of valence electrons as Neon.
B. Xenon because it has the same number of neutrons as Neon
C. Xenon because it has the same number of electrons as Neon
D. Xenon because it has the same number of protons as Neon
Please help
Chemistry
1 answer:
Serggg [28]3 years ago
7 0
The answer would be B
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Identify and label the Brønsted-Lowry acid, its conjugate base, the Brønsted-Lowry base, and its conjugate acid in each of the f
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Explanation:

As per Brønsted-Lowry concept of acids and bases, chemical species which donate proton are called Brønsted-Lowry acids.

The chemical species which accept proton are called Brønsted-Lowry base.

(a) HNO_3 + H_2O \rightarrow H_3O^+ + NO_3^-

HNO_3 is Bronsted lowry acid and NO_3^- is its conjugate base.

H_2O is Bronsted lowry base and H_3O^+ is its conjugate acid.

(b)

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CN^- is Bronsted lowry base and HCN is its conjugate acid.

H_2O is Bronsted lowry acid and OH^- is its conjugate base.

(c)

H_2SO_4 + Cl^- \rightarrow HCl + HSO_4^-

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HSO_4^-+OH^- \rightarrow SO_4^{2-}+H_2O

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OH^- is Bronsted lowry base and H_2O is its conjugate acid.

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O_{2-}+H_2O \rightarrow 2OH^-

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6 0
3 years ago
Before tackling this problem, be sure you know how to find the antilog of a number using a scientific calculator.
dybincka [34]
<h2>Question:- </h2>

A solution has a pH of 5.4, the determination of [H+].

<h2>Given :- </h2>
  1. pH:- 5.4
  2. pH = - log[H+]

<h2>To find :- concentration of H+</h2>

<h2>Answer:- Antilog(-5.4) or 4× 10-⁶</h2>

<h2>Explanation:- </h2><h3>Formula:- pH = -log H+ </h3>

Take negative to other side

-pH = log H+

multiple Antilog on both side

(Antilog and log cancel each other )

Antilog (-pH) = [ H+ ]

New Formula :- Antilog (-pH) = [+H]

Now put the values of pH in new formula

Antilog (-5.4) = [+H]

we can write -5.4 as (-6+0.6) just to solve Antilog

Antilog ( -6+0.6 ) = [+H]

Antilog (-6) × Antilog (0.6) = [+H]

Antilog (-6)  = {10}^{ - 6} ,  \\ Antilog (0.6)  = 4

put the value in equation

{10}^{ - 6}   \times 4 = [H+] \\ 4 \times   {10}^{ - 6}  = [H+]

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