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vovikov84 [41]
3 years ago
10

Write a chemical equation depicting what happens to the sugar in water.

Chemistry
1 answer:
zysi [14]3 years ago
5 0
Assuming that you mean table sugar (sucrose), then at room temperature and without any catalyst, there is no reaction. 

However if you elevate and hold the temperature of the aqueous solution at 50 to 60 °C (especially in the presence of a suitable catalyst, like mineral acid) the sucrose dimer will split into glucose and fructose. This is called hydrolysis and the resulting solution is called an invert sugar solution. 

The reaction could be written as: 

C12H22O11 (sucrose) + H2O (water) → C6H12O6 (glucose) + C6H12O6 (fructose) 

or 

C12H22O11 (aq) + H2O (l) → C6H12O6 (aq) + C6H12O6 (aq) 

Notice that both of the produced sugars have the same empirical formula. Check with your instructor or in your textbook to see if more exact formulas are needed.
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Determine the ionic strength, μ, for each of the solutions. Assume complete dissociation of each salt and ignore any hydrolysis
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Answer:

The answers are: (a )0.0058 M; (b) 0.00681 M; (c) 0.006912 M

Explanation:

Ionic strenght= μ= 1/2 ∑ c z²

Where c is the concentration of each ion (in M) and z is the charge of the ion. So, to calculate the ionic strenght of a solution you have to know the concentration of each ion and their charges. For this, the dissociation equilibrium is required.

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Conc Cl⁻= 0.00580 M

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b) CaBr₂  →  Ca²⁺ + 2 Br⁻

Conc Ca²⁺= 0.00227 M

Conc Br⁻= 2 x 0.00227 M= 0.00454 M

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μ= 1/2 (0.00227 M (4)) + (0.00454 M)

μ= 0.00681 M

c) The solution has two dissociation equilibria:

Mg(NO₃)₂ → Mg²⁺ + 2 NO₃⁻

La(NO₃)₃ → La³⁺ + 3 NO₃⁻

Conc Mg²⁺= 0.000752 M

Conc NO₃⁻= 2 x (0.000752 M) + 3 x (0.000776 M)= 0.003832 M

Conc  La³⁺= 0.000776 M

μ= 1/2 ((Conc Mg²⁺)(+2)²)+ ((Conc NO₃⁻)(-1)²) + ((Conc  La³⁺)(+3)²)

μ= 1/2 (0.000752 M(4)) + (0.003832 M) + (0.000776 M)(9))

μ= 0.006912 M

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