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Dennis_Churaev [7]
3 years ago
14

What are 4 ways that water can go through a physical change?

Chemistry
1 answer:
zlopas [31]3 years ago
5 0
Being frozen, staying a liquid, becoming ice, and becoming a gas (steam)
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If you need some points and are good at science help!
bonufazy [111]

Answer:

region 2 and region 3

Explanation:

you can tell by the color of the land my friends^^

6 0
3 years ago
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Which is the balanced chemical equation representing the reaction between barium sulfide and platinum fluoride? BaS + PtF2 BaF2
Svetllana [295]

BAS might be an improperly capitalized: BAs, BaS

PTF2 might be an improperly capitalized: PtF2

BAF2 might be an improperly capitalized: BaF2

PTS might be an improperly capitalized: PtS

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2 years ago
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Write in scientific form<br> 0.00580 → <br><br> 3000 → <br><br> 0.000908 → <br><br> 200. →
vagabundo [1.1K]

Answer:

Explanation:

0.00580=5.8*10^-3

3000=3.0*10^3

0.000908=9.08*10^-4

200.=2.0*10^2

6 0
2 years ago
A solution is prepared by mixing 93.0 mL of 5.00 M HCl and 37.0 mL of 8.00 M HNO3. Water is then added until the final volume is
Charra [1.4K]

Answer:

[H^{+}] = 0.761 \frac{mol}{L}

[OH^{-}]=1.33X10^{-14}\frac{mol}{L}

pH = 0.119

Explanation:

HCl and HNO₃ both dissociate completely in water. A simple method is to determine the number of moles of proton from both these acids and dividing it by the total volume of solution.

n_{H^{+} } from HCl = [HCl](\frac{mol}{L}). V_{HCl}(L)  \\ n_{H^{+} } from HNO_{3}  = [HNO_{3}](\frac{mol}{L}). V_{HNO_{3}}(L)

Here, n is the number of moles and V is the volume. From the given data moles can be calculated as follows

n_{H^{+} } from HCl = (5.00)(0.093)

n_{H^{+} } from HCl = 0.465 mol

n_{H^{+} } from HNO_{3}  = (8.00)(0.037)

n_{H^{+} } from HNO_{3}  = 0.296 mol

n_{H^{+}(total) } = 0.296 + 0.465

n_{H^{+}(total) } = 0.761 mol

For molar concentration of hydrogen ions:

[H^{+}]  = \frac{n_{H^{+}}(mol)}{V(L)}

[H^{+}] = \frac{0.761}{1.00}

[H^{+}] = 0.761 \frac{mol}{L}

From dissociation of water (Kw = 1.01 X 10⁻¹⁴ at 25°C) [OH⁻] can be determined as follows

K_{w} = [H^{+} ][OH^{-} ]

[OH^{-}]=\frac{Kw}{[H^{+}] }

[OH^{-}]=\frac{1.01X10-^{-14}}{0.761 }

[OH^{-}]=1.33X10^{-14}\frac{mol}{L}

The pH of the solution can be measured by the following formula:

pH = -log[H^{+} ]

pH = -log(0.761)

pH = 0.119

5 0
3 years ago
Conservation of Mass means:
Anarel [89]

Answer:

Conservation of mass mean mass cannot be created nor destroyed

Explanation:

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3 years ago
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