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3 years ago

What volume will a sample of F2 gas occupy in a syringe at 5.5 atm if the f2 has volume of 30 ml at 1.2 atm?

Chemistry

1 answer:

padilas [110]3 years ago

8 0

Answer:

<h3>The answer is 6.54 mL</h3>

Explanation:

To find the new volume we use the formula for Boyle's law which is

$P_1V_1 = P_2V_2$

Since we are finding the new volume

$V_2 = \frac{P_1V_1}{P_2} \\$

From the question we have

$V_2 = \frac{30 \times 1.2}{5.5} = \frac{36}{5.5} \\ = 6.54545454...$

We have the final answer as

Hope this helps you

You might be interested in

A mixture of c2h2 and ch4 has a total mass of 230.9 g. when this mixture reacts completely with excess oxygen, the co2 and h2o p

Salsk061 [2.6K]

Interesting problem. Thanks for posting.

C2H2 + (3/2)02 ====> H2O + 2CO2
CH4 + 2O2 =====> 2H2O + CO2

The molar mass of C2H2 = 2*12 + 2*1 = 26
The molar mass of CH4 = 1*12 + 4*1 = 16

The number of moles of C2H2 = x
The number of moles of CH4 = y
26x + 16y = 230.9 grams

For water we get (from the C2H2). Water has a molar mass of 2*1 + 16 = 18

x*18 See the balanced equation to see what it is the same number of moles as C2H2
From the methane we get
y*18
2*y* 18. Again see the balanced equation to see where that 2 came from.
18x + 36y is the total amount of water.

Now for the CO2. CO2 has a molar mass of 12 + 2*16 = 44
From C2H2 we get 2*44*x = 88x grams of CO2
From CH4 we get 1*y*44 grams of CO2
88x + 44y for CO2

Now we total to get the grand total of water and CO2
18x + 44y + 88x + 44y = 972.7 grams total.
106x + 88y = 972.7

Two equations, two unknowns, we should be able to solve this problem
26x + 16y = 230.9
106x + 88y = 972.7

I'm not going to go through the math unless you request me to do so.
x = 8.03 moles
y = 1.38 moles

The initial amount of C2H2 was 8.03 * 26 = 208.78
The initial amount of CH4 was 16*1.38 = 22.08
The total (as a check is 230.86 which is pretty close to the given amount.
So Methane's mass in the initial givens was 22.08 grams.

6 0

3 years ago

a couple of pennies have a mas of 5.2 grams. Asuming that the pennies are 100% percent copper,how many moles of copper are the p

dangina [55]

Answer:

5.2g copper (Cu) => 0.082 moles copper (2 sig.figs.)

Explanation:

mole conversions:

grams to moles => divide by formula wt.

moles to grams => multiply by formula wt.

gas volumes to moles => divide volume by 22.4Liters/mole (STP conditions only)

This problem:

mass to moles => divide by formula wt.

mass = 5.2g = 5.2g/63.5g/mole = 0.082 moles copper (2 sig.figs.)

5 0

3 years ago

How much heat energy must be absorbed to completely melt 35.0 grams of H2O(s) at 0°C?

Cerrena [4.2K]

(35/18.02)(6.02kJ)=11.6926 kiloJoules

5 0

4 years ago

Calcula la masa atómica del Hierro y las partículas subatómicas de cada uno de sus isótopos. Fe-54 (5.82%), Fe-56 (91.66%), Fe-5

tino4ka555 [31]

Answer:

La masa atómica del hierro es 55.847 gramos por mol.

Explanation:

Las masas molares de $Fe_{54}$ , $Fe_{56}$ , $Fe_{57}$ y $Fe_{58}$ son 53.940 gramos por mol, 55.935 gramos por mol, 56.935 gramos por mol y 57.933 gramos por mol, respectivamente. La masa atómica del hierro se determina mediante el siguiente promedio ponderado:

$M_{Fe} = \frac{5.82}{100}\times \left(53.940\,\frac{g}{mol} \right)+\frac{91.66}{100}\times (55.935\,\frac{g}{mol})+\frac{2.19}{100}\times \left(56.935\,\frac{g}{mol} \right)+\frac{0.33}{100}\times \left(57.933\,\frac{g}{mol} \right)$

$M_{Fe} = 55.847\,\frac{g}{mol}$

La masa atómica del hierro es 55.847 gramos por mol.

8 0

3 years ago

Why do atoms fond bonds

Setler [38]

They bond because they want to make their outer electron shells more stable

Hope this helps

Have a happy holidays

3 0

3 years ago