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Artyom0805 [142]
2 years ago
8

Rewrite the expression with rational exponents as a radical expression by extending the properties of integer exponents.

Mathematics
1 answer:
ra1l [238]2 years ago
6 0

The expression will be written as \rm \sqrt[8]{2^5}., the correct option is A.

<h3>What are Exponents?</h3>

Exponents are the base raised to a power, It is written in the superscript of a number.

The expression given in the statement can be written as

\rm \dfrac{ 2^{7/8}}{2^{1/4}}

By the Exponent rule,

\rm \dfrac{a^m}{a^n} = a^{m-n}

So the expression can be written as

<h3>=\rm { 2^{7/8-1/4}</h3>

=\rm 2^{5/8}

=\rm \sqrt[8]{2^5}

Therefore, in radical form, the expression will be written as \rm \sqrt[8]{2^5}., the correct option is A.

The complete question is

Rewrite the rational exponent as a radical by extending the properties of integer exponents.

2 to the 7 over 8 power, all over 2 to the 1 over 4 power

the eighth root of 2 to the fifth power

the fifth root of 2 to the eighth power

the square root of 2 to the 5 over 8 power

the fourth root of 2 to the sixth power

To know more about Exponents

brainly.com/question/5497425

#SPJ2

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Step-by-step explanation:

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Despejar la variable <br> 2x al cuadrado + 15= 113
Rudik [331]

Hola!

x = 7 , x = -7

Explicación:

Comienza restando 15 en cada lado:

2x^{2} + 15 -15=113-15

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2x^{2} =98

Ahora divide ambos lados por 2:

\frac{2x^{2} }{2} =\frac{98}{2}

Usted obtiene:

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Como la ecuación está al cuadrado, tendrás que hacer:

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que te da: x=\sqrt{49} , x =-\sqrt{49}

Entonces:

\sqrt{49}=7 , -\sqrt{49}  = -7

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XY-XZ
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(09.05 MC) Derek kicks a soccer ball off the ground and in the air, with an initial velocity of 31 feet per second. Using the fo
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In order to find the maximum of the function, we have to find the roots of the first derivative. 
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This gives us the time at which the ball reaches its maximum height. 
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H(0)=0=-16(0)^2+v(0)+s\\ s=0
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Expanding logarithmic Expression In Exercise,Use the properties of logarithms to rewrite the expression as a sum,difference,or m
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\frac{1}{2}ln(2x)-\frac{1}{2}ln(x^2-1)

Step-by-step explanation:

In 2x/(x^2 - 1)1/2

ln(\frac{2x}{x^2-1} )^\frac{1}{2}

Apply the property of natural log

ln x^m = m ln(x) move the exponent before ln

ln(\frac{2x}{x^2-1} )^\frac{1}{2}

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\frac{1}{2}(ln(2x)-ln(x^2-1))

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\frac{1}{2}ln(2x)-\frac{1}{2}ln(x^2-1)

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