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eimsori [14]
3 years ago
15

Floyd is an aspiring music artist. He has a record contract that pays him a base rate of $200 a month and an additional $12 for

each album that he sells. Last month he earned a total of $644
Write an equation to determine the number of albums (a) Floyd sold last month.
Find the number of albums Floyd sold last month.
Mathematics
1 answer:
Roman55 [17]3 years ago
7 0

Answer:

200 + 12n = 644  Answer: 37

Step-by-step explanation:

200 + 12n = 644

12n = 444

n = 37

Floyd sold 37 albums last month

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Solve for missing variables on these two seperate questions.
Iteru [2.4K]

Answer:?

Step-by-step explanation:

8 0
3 years ago
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What is the slope of a line parallel to the line whose equation is
Lyrx [107]

Answer:

slope = 3

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Given

9x - 3y = - 54 ( subtract 9x from both sides )

- 3y = - 9x - 54 ( divide all terms by 0 3 )

y = 3x + 18 ← in slope- intercept form

with slope m = 3

Parallel lines have equal slopes, thus

slope of parallel line is 3

8 0
3 years ago
The diameter of a sphere is 16 cm. What is the sphere's volume? Round to the nearest tenth.
ohaa [14]

Answer:

V ≈ 2144.70 cm^3

Step-by-step explanation:

Radius is going to be used instead of the diameter. Half of 16 is 8, and so that will be the value that shall be used.

V = (4/3)\pi (8)^3

V ≈ 2144.66 cm^3

V ≈ 2144.70 cm^3

5 0
3 years ago
1. Approximate the given quantity using a Taylor polynomial with n3.
Jet001 [13]

Answer:

See the explanation for the answer.

Step-by-step explanation:

Given function:

f(x) = x^{1/4}

The n-th order Taylor polynomial for function f with its center at a is:

p_{n}(x) = f(a) + f'(a) (x-a)+\frac{f''(a)}{2!} (x-a)^{2} +...+\frac{f^{(n)}a}{n!} (x-a)^{n}

As n = 3  So,

p_{3}(x) = f(a) + f'(a) (x-a)+\frac{f''(a)}{2!} (x-a)^{2} +...+\frac{f^{(3)}a}{3!} (x-a)^{3}

p_{3}(x) = f(a) + f'(a) (x-a)+\frac{f''(a)}{2!} (x-a)^{2} +...+\frac{f^{(3)}a}{6} (x-a)^{3}

p_{3}(x) = a^{1/4} + \frac{1}{4a^{ 3/4} }  (x-a)+ (\frac{1}{2})(-\frac{3}{16a^{7/4} } ) (x-a)^{2} +  (\frac{1}{6})(\frac{21}{64a^{11/4} } ) (x-a)^{3}

p_{3}(x) = 81^{1/4} + \frac{1}{4(81)^{ 3/4} }  (x-81)+ (\frac{1}{2})(-\frac{3}{16(81)^{7/4} } ) (x-81)^{2} +  (\frac{1}{6})(\frac{21}{64(81)^{11/4} } ) (x-81)^{3}

p_{3} (x) = 3 + 0.0092592593 (x - 81) + 1/2 ( - 0.000085733882) (x - 81)² + 1/6  

                                                                                  (0.0000018522752) (x-81)³

p_{3} (x)  =  0.0092592593 x - 0.000042866941 (x - 81)² + 0.00000030871254

                                                                                                       (x-81)³ + 2.25

Hence approximation at given quantity i.e.

x = 94

Putting x = 94

p_{3} (94)  =  0.0092592593 (94) - 0.000042866941 (94 - 81)² +          

                                                                 0.00000030871254 (94-81)³ + 2.25

         = 0.87037 03742 - 0.000042866941 (13)² + 0.00000030871254(13)³ +    

                                                                                                                       2.25

         = 0.87037 03742 - 0.000042866941 (169) +  

                                                                      0.00000030871254(2197) + 2.25

         = 0.87037 03742 - 0.007244513029 + 0.0006782414503 + 2.25

p_{3} (94)  = 3.113804102621

Compute the absolute error in the approximation assuming the exact value is given by a calculator.

Compute \sqrt[4]{94} as 94^{1/4} using calculator

Exact value:

E_{a}(94) = 3.113737258478

Compute absolute error:

Err = | 3.113804102621 - 3.113737258478 |

Err (94)  = 0.000066844143

If you round off the values then you get error as:

|3.11380 - 3.113737| = 0.000063

Err (94)  = 0.000063

If you round off the values up to 4 decimal places then you get error as:

|3.1138 - 3.1137| = 0.0001

Err (94)  = 0.0001

4 0
3 years ago
Mr.Joshi gave 1/3 of his money to his son, 1/5 of it to charity and the remaining to his wife who got Rs.42,000. What was the to
tatyana61 [14]

The son gets 1/3 of 42,000, so you divide 42,000 by 3 and get the amount Mr. Joshi gave to his son. Then you do the same for charity, but instead divide 42,000 by 5. Then you add both values and subtract them from 42,000, and then you have what he gave to his wife.

x (amount wife got) = 42,000 - [(42,000/3) + (42,000/5]

x = 42,000 - [14000+8400]

x = 42,000 - 22,400

x = 19,600

Hope this helps!

8 0
3 years ago
Read 2 more answers
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