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Anna007 [38]
2 years ago
15

Chris is trimming trees. He can trim 2/3 of a tree in 1/2 of an hour. At what rate can Chris trim trees​

Mathematics
2 answers:
malfutka [58]2 years ago
8 0

Answer:

he trims i 1 and 1/3 trees an hour

it would take him 45 minutes to trim 1 tree

Step-by-step explanation:

Svetllana [295]2 years ago
6 0

Answer:

1 tree every 45 mins

Step-by-step explanation:

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Which gives the correct values for points A, B, C, and D?
beks73 [17]

Answer:

The correct answer for this problem is the 2nd one because all you have to do is count how far each one is from -1 and -2

Step-by-step explanation:

5 0
3 years ago
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HELPPPP PLEASEEE IM BEGGING SOMEONE PLEASE PLEASE HELP
pychu [463]

Given:

The figure of a rhombus QRST.

To find:

A. The value of x.

B. The measure of angle RQP.

Solution:

A. We need to find the value of x.

We know that the diagonals of a rhombus are perpendicular bisectors. It means the angles on the intersection of diagonals are right angles.

m\angle RPS=90^\circ                       [Right angle]

(5x+15)^\circ=90^\circ

(5x+15)=90

5x=90-15

5x=75

Divide both sides by 5.

x=\dfrac{75}{5}

x=15

Therefore, the value of x is 15.

B. We need to find the measure of angle RQP.

From the given figure, it is clear that

m\angle RQP=(2x+3)^\circ

Putting x=15, we get

m\angle RQP=(2(15)+3)^\circ

m\angle RQP=(30+3)^\circ

m\angle RQP=33^\circ

Therefore, the measure of angle RQP is 33 degrees.

8 0
2 years ago
Find the rule and complete the
Shtirlitz [24]

Answer:

7

Step-by-step explanation:

12-7=5

or

5+7=12

3 0
2 years ago
A cylinder is full at 471 cubic centimeters and has a radius of 5 centimeters. it currently contains 314 centimeters of water.
solniwko [45]
A cylinder is full at 471 cubic centimeters and has a radius of 5 centimeters. it currently contains 314 centimeters of water.
what is the difference between the height of the water in the full cylinder and the height when 314 cubic centimeters of water remains in the cylinder?
use 3.14 for pi
310 cm
6 0
3 years ago
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If each data is increased by a constant K then find it's mean ?? answer fast pleaseeeeeeeeeee​
MArishka [77]

Answer:

The mean is also increased by the constant k.

Step-by-step explanation:

Suppose that we have the set of N elements

{x₁, x₂, x₃, ..., xₙ}

The mean of this set is:

M = (x₁ + x₂ + x₃ + ... + xₙ)/N

Now if we increase each element of our set by a constant K, then our new set is:

{ (x₁ + k), (x₂ + k), ..., (xₙ + k)}

The mean of this set is:

M' = ( (x₁ + k) + (x₂ + k) + ... + (xₙ + k))/N

M' = (x₁ + x₂ + ... + xₙ + N*k)/N

We can rewrite this as:

M' = (x₁ + x₂ + ... + xₙ)/N + (k*N)/N

and  (x₁ + x₂ + ... + xₙ)/N was the original mean, then:

M' = M + (k*N)/N

M' = M + k

Then if we increase all the elements by a constant k, the mean is also increased by the same constant k.

6 0
3 years ago
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