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3 years ago

A photocopy machine can print 405 copies in 9 minutes. what is the unit rate the machine can produce in 1 minute

Mathematics

1 answer:

Zolol [24]3 years ago

3 0

Answer:45

Step-by-step explanation: divide 405 by 9

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287.5 rounded to nearest whole number

arlik [135]

Answer: I believe the answer is 88

~i hope that is answered your question correctly, have a gr8 day/night my friend!~

Step-by-step explanation:

4 0

2 years ago

Read 2 more answers

A quantity with an initial value of 9100 grows continuously at a rate of 0.85% per hour. What is the value of the quantity after

ycow [4]

Answer:

$10,962,54$

Step-by-step explanation:

we know that

The equation of a exponential growth is equal to

$y=a(1+r)^x$

where

a is the initial value

r is the rate of growth

x is the time in hours

y is the value of the quantity

we have

$a=9,100\\r=0.85\%=0.85/100=0.0085$

substitute

$y=9,100(1+0.0085)^x$

$y=9,100(1..0085)^x$

For x=22 hours

substitute

$y=9,100(1..0085)^{22} =10,962,54$

4 0

3 years ago

The family of solutions to the differential equation y ′ = −4xy3 is y = 1 √ C + 4x2 . Find the solution that satisfies the initi

slega [8]

Answer:

The correct option is 4

Step-by-step explanation:

The solution is given as

$y(x)=\frac{1}{\sqrt{C+4x^2}}$

Now for the initial condition the value of C is calculated as

$y(x)=\frac{1}{\sqrt{C+4x^2}}\\y(-2)=\frac{1}{\sqrt{C+4(-2)^2}}\\4=\frac{1}{\sqrt{C+4(4)}}\\4=\frac{1}{\sqrt{C+16}}\\16=\frac{1}{C+16}\\C+16=\frac{1}{16}\\C=\frac{1}{16}-16$

So the solution is given as

$y(x)=\frac{1}{\sqrt{C+4x^2}}\\y(x)=\frac{1}{\sqrt{\frac{1}{16}-16+4x^2}}$

Simplifying the equation as

$y(x)=\frac{1}{\sqrt{\frac{1}{16}-16+4x^2}}\\y(x)=\frac{1}{\sqrt{\frac{1-256+64x^2}{16}}}\\y(x)=\frac{\sqrt{16}}{\sqrt{{1-256+64x^2}}}\\y(x)=\frac{4}{\sqrt{{1+64(x^2-4)}}}$