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Alex73 [517]
3 years ago
13

Chad washes windows after school to make some extra money. He charges $5.50 to wash each window. If the customer provides the su

pplies, Chad deducts $3.25 from the total cost. One customer paid a total of $35.25 and did provide supplies. Which equation could be used to find the number of windows, w , that Chad washed for this customer? A) 5.5 w + 3.25 = 35.25 B) 5.5 w - 3.25 = 35.25 C) 5.5 w = 35.25 D) 5.5 - 3.25 w = 35.25
Mathematics
2 answers:
kap26 [50]3 years ago
8 0

Answer: D is correct if it is really (5.5-3.25)w=35.25

(Without parenthesis it doesn't work)

tatiyna3 years ago
3 0

Answer:

B) 5.5 w - 3.25 = 35.25

Step-by-step explanation:

Chad charges $5.50 per window. ( 5.50w )

Since Chad's customer brought supplies, Chad would deduct $3.25. ( - 3.25)

The customer would be charged $35.25 at the end. ( = 35.25 )

So, the total of the cost of the windows minus the discount would be $35.25.

5.50w - 3.25 = 35.25

Option B's equation would be most appropriate to solve for w.

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Write the related series for each finite sequence the. Evaluate the series. For problems 2,4,6. Thank you.
levacccp [35]
To evaluate the series we proceed as follows:
2. -5,-15,-25,-35,-45
The common difference is (-15--5)=-10
thus the series is an arithmetic sequence hence the explicit formula will be:
an=a+(n-1)d
thus the formula for the series is:
an=-5+(n-1)(-10)
an=-10n+5

4. 0.5, 0.25,0,...,-0.75
The common difference =0.25-0.5=-0.25
The sequence is an arithmetic sequence:
the explicit formula will be:
an=0.5-0.25(n-1)
an=-0.25n+0.75
thus
n=4
a4=-0.25*4+0.75=-0.25
when n=5
a5=-0.25*5+0.75=-0.5
when n=6
a6=-0.25*6+0.75=-0.75
the missing values are -0.25 and -0.5

6] 4.5,5.6,6.7, ....,11.1
common difference=5.6-4.5=1.1
the sequence is an arithmetic sequence
The explicit formula is:
an=4.5+1.1(n-1)
an=1.1n+3.4
when n=4
an=1.1*4+3.4
a4=7.8

when n=5
a5=1.1*5+3.4
a5=8.9

a6=1.1*6+3.4
a6=10
the missing values are: 7.8, 8.9, 10

6 0
4 years ago
Find the limit, if it exists. (If an answer does not exist, enter DNE.)
lys-0071 [83]

let's change some the 0.1 to say 1/10, just the fraction version of it.

\bf \lim\limits_{x\to \left( \frac{1}{10} \right)^-}~\cfrac{10x-1}{|10x^3-x^2|}\implies \lim\limits_{x\to \left( \frac{1}{10} \right)^-}~\cfrac{10(-x)-1}{10(-x)^3-(-x)^2}

\bf \cfrac{-10x-1}{-10x^3-x^2}\implies \cfrac{-10\left( \frac{1}{10} \right)-1}{-10\left( \frac{1}{10} \right)^3-\left( \frac{1}{10} \right)^2}\implies \cfrac{-1-1}{-\frac{1}{100}-\frac{1}{100}}\implies \cfrac{-2}{\frac{-2}{100}} \\\\\\ \cfrac{~~\begin{matrix} -2 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~}{1}\cdot \cfrac{100}{~~\begin{matrix} -2 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~}\implies 100

when checking an absolute value expression, we do the one-sided limits, since an absolute value expression is in effect a piecewise function with ± versions, so for the limit from the left we check the negative version.

8 0
3 years ago
Solve the inequality for x<br> 3^(6x+18)&lt;27^(3x)
Lera25 [3.4K]

Answer:

\displaystyle x > 6

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right  

Equality Properties

  • Multiplication Property of Equality
  • Division Property of Equality
  • Addition Property of Equality
  • Subtraction Property of Equality

<u>Algebra I</u>

  • Terms/Coefficients
  • Factoring

<u>Algebra II</u>

  • Exponential Rule [Powering]: \displaystyle (b^m)^n = b^{m \cdot n}
  • Solving exponential equations

Step-by-step explanation:

<u>Step 1: Define</u>

<em>Identify</em>

<em />\displaystyle 3^{6x + 18} < 27^{3x}<em />

<em />

<u>Step 2: Solve for </u><em><u>x</u></em>

  1. Rewrite:                                                                                                             \displaystyle 3^{6x + 18} < 3^{3(3x)}
  2. Set:                                                                                                                     \displaystyle 6x + 18 < 3(3x)
  3. Factor:                                                                                                               \displaystyle 3(2x + 6) < 3(3x)
  4. [Division Property of Equality] Divide 3 on both sides:                                  \displaystyle 2x + 6 < 3x
  5. [Subtraction Property of Equality] Subtract 3x on both sides:                       \displaystyle -x + 6 < 0
  6. [Subtraction Property of Equality] Subtract 6 on both sides:                        \displaystyle -x < -6
  7. [Division Property of Equality] Divide -1 on both sides:                                 \displaystyle x > 6
8 0
3 years ago
Read 2 more answers
A square-based pyramid has a surface area of 561 cm². If the length of the base is
Naddik [55]

Step-by-step explanation:

The formula for the area of a square is:

A

=

s

2

Where:

A

is the area of the square.

s

is the length of the side of a square.

Substituting and solving for

s

gives:

225

cm

2

=

s

2

We can take the square root of each side of the equation giving:

√

225

cm

2

=

√

s

2

15

cm

=

s

s

=

15

cm

The formula for the perimeter of a square is:

p

=

4

s

Where:

p

is the perimeter of the square.

s

is the length of the side of a square.

Substituting for

s

from the solution for the previous formula and calculating

p

gives:

p

=

4

×

15

cm

p=60cm

please mark me as the brainliest answer and please follow me for more answers to your questions

6 0
4 years ago
PLEASE HELP!!! 10pts​
labwork [276]
<h3>I'll teach you how to solve (81x^-20 y^-16)^-3/4</h3>

---------------------------------------------------------------

(81x^-20 y^-16)^-3/4

Apply exponents rule:

(81x^-20 y^-16)^-3/4=

1 / (81x^-20 y^-16)^-3/4

Simplify (81x^-20 y^-16)^-3/4:

1/27/x^15 y^12

Apply the fraction rule:

x^15 y^12 / 27

Your Answer Is x^15 y^12 / 27

plz mark me as brainliest if this helped :)

8 0
3 years ago
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