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Lady bird [3.3K]

3 years ago

15

in the early spring the trout at big blue Lake Swim at a deph of 30 feet below sea level when the lake warms up in the summer th

e trout with 20 feet deeper than that at what position relative to sea-level do the trout swim in the summer?

1 answer:

Ludmilka [50]3 years ago

4 0

Answer:

-50 feet

Step-by-step explanation:

The trout is swimming 30 ft below sea level,if it were above sea level it would be positive but since its below it is negative. It then swims 20 feet lower so it would be -50 as a short cut you can use in problems like this one is to ignore the sign's and add it regularly then add the sign after the equation is done.

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A rectangular piece of metal is 25 in longer than it is wide. Squares with sides 5 in long are cut from the four corners and the

Licemer1 [7]

Answer:

The original length was 41 inches and the original width was 16 inches

Step-by-step explanation:

Let

x ----> the original length of the piece of metal

y ----> the original width of the piece of metal

we know that

When squares with sides 5 in long are cut from the four corners and the flaps are folded upward to form an open box

The dimensions of the box are

$L=(x-10)\ in\\W=(y-10)\ in\\H=5\ in$

The volume of the box is equal to

$V=(x-10)(y-10)5$

$V=930\ in^3$

so

$930=(x-10)(y-10)5$

simplify

$186=(x-10)(y-10)$ -----> equation A

Remember that

The piece of metal is 25 in longer than it is wide

so

$x=y+25$ ----> equation B

substitute equation B in equation A

$186=(y+25-10)(y-10)$

solve for y

$186=(y+15)(y-10)\\186=y^2-10y+15y-150\\y^2+5y-336=0$

Solve the quadratic equation by graphing

using a graphing tool

The solution is y=16

see the attached figure

Find the value of x

$x=16+25=41$

therefore

The original length was 41 inches and the original width was 16 inches

3 0

3 years ago

Factor completely: 2x4 − 32.

vazorg [7]

Answer:

Option b) is correct.

The completed factor of given expression is $2(x-2)(x+2)(x^2+4)$

Step-by-step explanation:

Given expression is $2x^4-32$

To find the completed factor for the given expression:

$2x^4-32$ :

Taking the common number "2" outside to the above expression we get

$2x^4-32=2(x^4-16)$

Now rewritting the above expression as below

$=2(x^4-2^4)$ (since 16 can be written as the number 2 to the power of 4)

$=2((x^2)^2-(2^2)^2)$

The above expression is of the form $a^2-b^2=(a+b)(a-b)$

Here $a=x^2$ and $b=2^2$

Therefore it becomes

$=2(x^2+2^2)(x^2-2^2)$

$=2(x^2+4)(x^2-2^2)$

The above expression is of the form $a^2-b^2=(a+b)(a-b)$

Here $a=x$ and $b=2$

Therefore it becomes

$=2(x^2+4)(x+2)(x-2)$

$=2(x+2)(x-2)(x^2+4)$

Therefore $=2(x+2)(x-2)(x^2+4)$

$2x^4-32=2(x-2)(x+2)(x^2+4)$

Option b) is correct.

The completed factor of given expression is $2(x-2)(x+2)(x^2+4)$

3 0

4 years ago

Read 2 more answers

Combine like terms. What is a simpler form of each expression?<br> 30 - 5d - C + 3d

borishaifa [10]

30 - 5d - c + 3d

In this equation there are two numbers which have the letter d with them. These would be like terms.

You have -5d + 3d which equals -2d

The simplified form would be 30 -2d -c

4 0

3 years ago

Read 2 more answers

How do you evaluate 11 c 5

swat32

You have 11 items and you need to choose 5 of the 11.
There are 462 ways to choose them.
The formula is :
11! / (5!6!)
n!/(r!(n-r)!)

6 0

3 years ago

Formula to calculate variance

finlep [7]

Answer:

sample variance

the value of the one observation

the mean value of all observations

the number of observations

Step-by-step explanation:

8 0

3 years ago