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klemol [59]
3 years ago
13

If f(x) = 2x + 3 and g(x) = (x - 3)/2, what is the value of f[g(-5)]?

Mathematics
1 answer:
kap26 [50]3 years ago
3 0
<span>If f(x) = 2x + 3 and g(x) = (x - 3)/2, what is the value of f[g(-5)]? f[g(-5)] means substitute -5 for x in the right side of g(x), simplify, then substitute what you get for x in the right side of f(x), then simplify. It's a "double substitution". To find f[g(-5)], work it from the inside out. In f[g(-5)], do only the inside part first. In this case the inside part if the red part g(-5) g(-5) means to substitute -5 for x in g(x) = (x - 3)/2 So we take out the x's and we have g( ) = ( - 3)/2 Now we put -5's where we took out the x's, and we now have g(-5) = (-5 - 3)/2 Then we simplify: g(-5) = (-8)/2 g(-5) = -4 Now we have the g(-5)] f[g(-5)] means to substitute g(-5) for x in f[x] = 2x + 3 So we take out the x's and we have f[ ] = 2[ ] + 3 Now we put g(-5)'s where we took out the x's, and we now have f[g(-5)] = 2[g(-5)] + 3 But we have now found that g(-5) = -4, we can put that in place of the g(-5)'s and we get f[g(-5)] = f[-4] But then f(-4) means to substitute -4 for x in f(x) = 2x + 3 so f(-4) = 2(-4) + 3 then we simplify f(-4) = -8 + 3 f(-4) = -5 So f[g(-5)] = f(-4) = -5</span>
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Answer

given,

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assume the observed statistic is = 11.1

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assuming the number of sample = 4

n = 4

Hypothesis test:

H₀ : μ≥ 12

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now,

significant level α = 0.05

z* = \dfrac{\bar{X}-\mu}{\dfrac{\sigma}{\sqrt{n}}}

z* = \dfrac{11.1-12}{\dfrac{0.5}{\sqrt{4}}}

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Test statistics, Z* = -3.60

P-value

P(Z<-3.60) = 0.002 (from z- table)

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now,

reject the value of H₀ when P-value < α

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since, it is less P-value < α , we have to reject the null hypothesis

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3 years ago
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stira [4]

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(-8, 6) --> (-6, 8)

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I hope this helped and have a good rest of your day!

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