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erma4kov [3.2K]

2 years ago

5

If ∠GHJ≅∠IHJ and GJ=99, what is IJ?

1 answer:

quester [9]2 years ago

6 0

Answer:

99

Step-by-step explanation:

Triangles GJH and IJH are congruent, so GJ=IJ=99.

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The endpoints of ab are a(1,4) and b(6,-1). If point c divides ab in the ratio 2:3, the coordinates of c are ?. If point d divid

aliya0001 [1]

Answer:

see explanation

Step-by-step explanation:

Find the coordinates of c using the section formula

$x_{c}$ = $\frac{(3(1)+(2(6)}{2+3}$ = $\frac{3+12}{5}$ = 3

$y_{c}$ = $\frac{(3(4))+(2(-1))}{2+3}$ = $\frac{12-2}{5}$ = 2

coordinates of c = (3, 2)

Similarly to find the coordinates of d

$x_{d}$ = $\frac{x(2(1))+(3(3))}{3+2}$ = $\frac{2+9}{5}$ = $\frac{11}{5}$

$y_{d}$ = $\frac{(2(4))+(3(2))}{3+2}$ = $\frac{8+6}{5}$ = $\frac{14}{5}$

coordinates of d = ( $\frac{11}{5}$ , $\frac{14}{5}$ )

4 0

2 years ago

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I need help anyone know

kaheart [24]

Answer:

yes ur correct its nonlinear lol

Step-by-step explanation:

6 0

3 years ago

What is 9k + 1 = ─9 + 7k solved for the variable???

m_a_m_a [10]

Answer:

k = -5

Step-by-step explanation:

The variable is k

9k + 1 = -9 + 7k

-7k -1

2k = -10

2k/2 -10/2

k = -5

:)

4 0

2 years ago

What is the square root of 9389276537

miv72 [106K]

96898.2793294081151405

6 0

3 years ago

Read 2 more answers

Which of the following have the property that a(x)=a−1(x)? I. y=x II. y=1/x III.y=x^2 IV. y=x^3 A. I and II, only B. IV, only C.

valentina_108 [34]

Answer:

<em>Correct answer:</em>

<em>A. I and II</em>

<em></em>

Step-by-step explanation:

First of all, let us have a look at the steps of finding inverse of a function.

1. Replace y with x and x with y.

2. Solve for y.

3. Replace y with $f^{-1}(x)$

Given that:

$I.\ y=x \\II.\ y=\dfrac{1}x \\III.\ y=x^2 \\IV.\ y=x^3$

Now, let us find inverse of each option one by one.

I. y = x, a(x) = x

Replacing y with and x with y:

x = y

x = $a^{-1}(x)$ = $a(x)$ Hence, I is true.

II. $y =\dfrac{1}{x}$

Replacing y with and x with y:

$x =\dfrac{1}{y}$

$x=\dfrac{1}{a^{-1}(x)}$

$\Rightarrow a^{-1}(x) = \dfrac{1}{x}$

$a^{-1}(x)$ = $a(x)$ Hence, II is true.

III. $y =x^{2}$

Replacing y with and x with y:

$x =y^{2}\\\Rightarrow y = \sqrt x\\\Rightarrow a^{-1}(x) = \sqrt{x} \ne a(x)$

Hence, III is not true.

IV. $y =x^{3}$

Replacing y with and x with y:

$x =y^{3}\\\Rightarrow y = \sqrt[3] x\\\Rightarrow a^{-1}(x) = \sqrt[3]{x} \ne a(x)$

Hence, IV is not true.

<em>Correct answer:</em>

<em>A. I and II</em>

<em></em>

4 0

3 years ago