Answer:
1800J
Explanation:
Given parameters:
Weight of the book = 20N
Total distance covered = 45m + 15m + 30m = 90m
Unknown:
Total work performed on the books = ?
Solution:
To solve this problem we must understand that work done is the force applied to move a body through a certain distance.
So;
Work done = Force x distance
Work done = 20 x 90 = 1800J
Answer:
d = 19.796m
Explanation:
Since the ball is in the air for 4.02 seconds, the ball should reach the maximum point from the ground in half the total time, therefore, t=2.01s to reach maximum height. At the maximum height, the velocity in the y-direction is 0.
So we know t=2.01, vi=0, g=a=9.8m/s and we are solving for d.
Next, you look for a kinematic equation that has these parameters and the one you should choose is:
Now by substituting values in, we get
d = 19.796m
Answer:
C) W = - 190 J
Explanation:
Notation
Wf = work done by the friction force (unknown)
Ff = force of the friction
d = distance travelled by the box = (2 pi 1.82 m) = 11.435 m
Answer:
The answer is Gravitational pull
Answer:
-5.396Joules
Explanation:
Work is said to be done when a force causes a body to move through a distance and acts in the direction of the force.
Work done = Force × Distance
Given force = mg
Force = 2.20×9.81
Force applied on the string = 21.58N
Distance will be the difference in height = 4.75-5.00
= 0.25m
Negative work done on the pendulum during the first entirely oscillation = 21.58×0.25
= -5.396Joules
