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nata0808 [166]
2 years ago
14

Two objects experienced the same displacement in the same amount of time. The two objects must have the same -

Physics
1 answer:
nikdorinn [45]2 years ago
6 0

If two object experiences the same displacement at the same time, the two objects must have the same average velocity.

The average velocity of an object is defined as the change in displacement per change in time of motion. This can be written as follows;

avg. \ velocity = \frac{\Delta \ displacement }{\Delta \ time} \\\\V = \frac{\Delta \ x}{\Delta t}

If two object experiences the same displacement at the same time, it means that the change in displacement with time is constant.

\frac{\Delta x_1}{\Delta t_1} = \frac{\Delta x_2}{\Delta t_2} = V_{avg}

Thus, we can conclude that if two object experiences the same displacement at the same time, the two objects must have the same average velocity.

Learn more here: brainly.com/question/23856383

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A police siren of frequency fsiren is attached to a vibrating platform. The platform and siren oscillate up and down in simple h
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Answer:

he maximum frequency occurs when the denominator is minimum

 f’= f₀  \frac{343}{343 + v_s}

Explanation:

This is a doppler effect exercise, where the sound source is moving

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           f ’=f_o  \frac{v}{v+v_{sy}}  Alexandrian source of the observer

the maximum frequency occurs when the denominator is minimum, for both it is the point of maximum approach of the two objects

          f’= f₀  \frac{343}{343 + v_s}

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Atoms with electronegativity differences below 0.4 generally form covalent<br>bonds. True or False​
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Answer:

True

Explanation:

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on a very muddy football field, a 120 kg linebacker tackles an 75 kg halfback. immediately before the collision, the linebacker
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<u>Momentum</u> 
- a vector quantity; has both magnitude and direction
- has the same direction as object's velocity
- can be represented by components x & y.

Find linebacker momentum given m₁ = 120kg, v₁ = 8.6 m/s north
P₁ = m₁v₁
P₁ = (120)(8.6)
[ P₁ = 1032 kg·m/s ] = y-component, linebacker momentum

Find halfback momentum given m₂ = 75kg, v₂ = 7.4 m/s east
P₂ = m₂v₂
P₂ = (75)(7.4)
[ P₂ = 555 kg·m/s ] = x-component, halfback momentum

Find total momentum using x and y components.
P = √(P₁)² + (P₂)²
P = √(1032)² + (555)²
[[ P = 1171.77 kg·m/s ]] = magnitude 

!! Finally, to find the magnitude of velocity, take the divide magnitude of momentum by the total mass of the players.
P = mv
P = (m₁ + m₂)v
1171.77 = (120 + 75)v      <em>[solve for v]</em>
<em />v = 1171.77/195
v = 6.0091 ≈ 6.0 m/s

If asked to find direction, take inverse tan of x and y components.
tanθ = (y/x)
θ = tan⁻¹(1032/555)
[ θ = 61.73° north of east. ]

The magnitude of the velocity at which the two players move together immediately after the collision is approximately 6.0 m/s.
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