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Gekata [30.6K]
3 years ago
11

A long solenoid that has 1 170 turns uniformly distributed over a length of 0.420 m produces a magnetic field of magnitude 1.00

10-4 T at its center. What current is required in the windings for that to occur?
Physics
1 answer:
AysviL [449]3 years ago
6 0

I = 28.6mA.

The magnetic field in the center of a solenoid is given by:

B = μ₀NI/L

Clear I from the equation above, we obtain:

I = BL/μ₀N

With B = 1.00 x 10⁻⁴T, L = 0.42m, μ₀ = 4π x 10⁻⁷T.m/A  and N = 1170turns

I = [(1.00 x 10⁻⁴T)(0.42m)]/[(4π x 10⁻⁷T.m/A)(1170turns)]

I = 0.0286A

I = 28.6mA

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La distancia por carretera de Chitré a Parita es de 12 km; exprese en pies ésta distanciaLa distancia por carretera de Chitré a
densk [106]

Answer:

La distancia por carretera de Chitré a Parita es de 12 km o 39370.08 pies.

Explanation:

La regla de tres es una forma de resolver problemas de proporcionalidad entre tres valores conocidos y un valor desconocido, estableciendo una relación de proporcionalidad entre todos ellos.

Si la relación entre las magnitudes es directa, es decir, cuando una magnitud aumenta, también lo hace la otra (o cuando una magnitud disminuye, también lo hace la otra), se debe aplicar la regla directa de tres. Para resolver una regla directa de tres, se debe seguir la siguiente fórmula, siendo a, b y c los valores conocidos y x el valor a determinar:

a ⇒ b

c ⇒ x

Entonces x=\frac{c*b}{a}

La regla directa de tres es la regla que se aplica en este caso donde hay un cambio de unidades. Para realizar esta conversión de unidades, primero debes saber que 1 km = 3280,84 pies. Entonces, si 1 km son 3280,84 pies, ¿cuántos pies son 12 km?

1 km ⇒ 3280.84 pies

12 km ⇒ x

x=\frac{12 km*3280.84 pies}{1 km}

x= 39370.08 pies

<u><em>La distancia por carretera de Chitré a Parita es de 12 km o 39370.08 pies.</em></u>

7 0
2 years ago
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siniylev [52]
2 is the answer so mark it
7 0
3 years ago
What is the magnite of the net displacement of the mouse?
agasfer [191]

Complete Question

A field mouse trying to escape a hawk runs east for 5.0m, darts southeast for 3.0m, then drops 1.0m down a hole into its burrow. What is the magnitude of the net displacement of the mouse?

Answer:

The  values is  s =  7.49 \  m

Explanation:

From the question we are told that

   The  distance it travels eastward is  x =  5.0 \ m

   The distance it travel towards the southeast  is l  =  3.0\  m

   The distance it travel towards the south is  z =  1 \  m

 

Let x-axis  be east

      y-axis  south

       z-axis into the ground

The angle made between east and south is  \theta  =  45^o

The displacement toward x-axis is

       x =  5 +  3cos(45)

       x =  7.12

 The  displacement toward the y-axis is  

     y  =  3 *  sin (45)

      y =  2.123

Now the overall displacement of the rat is mathematically evaluated as

        s =  \sqrt{7.12^2 +  2.12^2 +  1^2}

      s =  7.49 \  m

     

   

3 0
3 years ago
How could you create an investigation to determine the pitch of this wave?
Musya8 [376]

Answer:

In order to make a sound wave have a higher pitch you increase the frequency.

In order to increase the volume of a sound wave, you have to increase the amplitude.

Hope this helps!

6 0
3 years ago
A person on a cruise ship is doing laps on the promenade deck. On one portion of the track the person is moving north with a spe
Aleksandr-060686 [28]

T<u>he direction of motion</u> of the person relative to the water is <u>16.7° north of east.</u>

Why?

We can solve the problem by applying the Pitagorean Theorem, where the first speed (to the north) and the second speed (to the east) corresponds to two legs of the right triangle formed with them. (north and east directions are perpendicular each other)

We can calculate the angle that give the direction using the following formula:

Tan(\alpha)=\frac{NorthSpeed}{EastSpeed}\\\\Tan(\alpha)^{-1}=Tan(\frac{NorthSpeed}{EastSpeed})^{-1}\\\\\alpha=Tan(\frac{NorthSpeed}{EastSpeed})^{-1}

Now, substituting the given information we have:

alpha=Tan(\frac{NorthSpeed}{EastSpeed})^{-1}

\alpha =Tan(\frac{3.6\frac{m}{s} }{12\frac{m}{s} })^{-1}\\\\\alpha =Tan(0.3)^{-1}=16.69\°(North-East)=16.7\°(North-East)

Hence, we have that <u>the direction of motion</u> of the person relative to the water is 16.7° north of east.

Have a nice day!

7 0
2 years ago
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