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valina [46]
3 years ago
12

In which type of wetland are you most likely to find carnivorous plants?

Physics
2 answers:
pshichka [43]3 years ago
7 0

carnivorous plants are found in (bog)

because they adopt to grow where soil is thin and poor.

hope this answer is what your looking for.

zysi [14]3 years ago
6 0
The type of wetland u are most likely to find carnivorous plant would be a bog.
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An object attached to an ideal spring oscillates with an angular frequency of 2.81 rad/s. the object has a maximum displacement
NikAS [45]
Ω = 2.81
A = 0.232
k = 29.8

x = A cos(ωt + Ф)

at t = 0:
x = A = A cos(ωt + Ф) = A cos(Ф)
Ф = 0

at t = 1.42, with Ф = 0:
x = A cos(ωt) 

U = 1/2 k x² = 1/2 k [A cos(ωt)]²
4 0
3 years ago
Where does these choices go?
murzikaleks [220]

Answer:

Nothing goes to Kinetic Energy

Both-1, 2, 4

Potential Energy-3 and 5

Explanation:

6 0
3 years ago
The gravitational force between two objects is f. If masses of both objects are halved without changing distance between them, t
Marrrta [24]

The gravitation force is quartered when two objects' masses are halved without changing their distance.

Gravitational law states that the force of attraction and repulsion between two objects is directly proportional to the product of their masses and inversely proportional to the square of their distance apart.

F=(KM1 M2)/r^2

K= Gravitation force constant

M1M2 = masses of the object

r = distance between objects

When M1 and M2 are halved, it becomes M1/2 and M2/2

F=(K M1/2 x M2/2)/r^2

F=(K (M1 x M2)/4)/r^2

F=(KM1 x M2)/(4r^2 )

Recall

F=(KM1 x M2)/r^2

Therefore

F=F/4

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7 0
2 years ago
Ma puteti ajuta sa rezolv la fizica o problema ?
xxTIMURxx [149]
Care este problema? Btw why are you speaking Romanian 
7 0
3 years ago
A rectangular loop of area A is placed in a region where the magnetic field is perpendicular to the plane of the loop. The magni
mina [271]

Answer:

Induced emf, \epsilon=-A\dfrac{B_{max}e^{-t/\tau}}{\tau}

Explanation:

The varying magnetic field with time t is given by according to equation as :

B=B_{max}e^{-t/\tau}

Where

B_{max}\ and\ t are constant

Let \epsilon is the emf induced in the loop as a function of time. We know that the rate of change of magnetic flux is equal to the induced emf as:

\epsilon=-\dfrac{d\phi}{dt}

\epsilon=-\dfrac{d(BA)}{dt}

\epsilon=-A\dfrac{d(B)}{dt}

\epsilon=-A\dfrac{d(B_{max}e^{-t/\tau})}{dt}

\epsilon=A\dfrac{B_{max}e^{-t/\tau}}{\tau}

So, the induced emf in the loop as a function of time is A\dfrac{B_{max}e^{-t/\tau}}{\tau}. Hence, this is the required solution.

7 0
3 years ago
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