<span>sin A cos B=1/2[sin(A-B)+sin(A+B)]
sin(at)*cos(2at)=1/2[sin(3at)-sin(at)]</span>
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Answer:
10
Step-by-step explanation:
Z ^2+11=111
Z ^2=100
Z=10
<span><span> combine like terms4ln(x) = 8
</span><span>divide both sides by 4.ln(x) = 2
</span><span>exponentiate both sides.<span>eln(x) = e^2</span>
</span><span>inverse property of exponents and logs <span>x = e^<span>2
pls return favor and answer question in profile pls
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Answer:
It would be 70 thousand
Step-by-step explanation: