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ella [17]
3 years ago
10

Help help help help help help help help!!!!

Mathematics
2 answers:
mina [271]3 years ago
8 0

Answer:

c

Step-by-step explanation:

stealth61 [152]3 years ago
8 0

Answer:

c is the answer have a nice day

Step-by-step explanation:

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Lisha has taken out a loan for $2000 to buy a car. She plans to pay back the loan at a rate of $50 per month. RaShana has borrow
chubhunter [2.5K]
It will take her 20 months
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3 years ago
Solve x2 = 12x – 15 by completing the square. Which is the solution set of the equation?
Nady [450]
For this case we have the following polynomial:
 x ^ 2 = 12x - 15

 The first thing to do is to place the variables on the same side of the equation.
 We have then:
 x ^ 2 - 12x = -15

 We complete the square by adding the term (b / 2) ^ 2 on both sides of the equation.
 We have then:
 x ^ 2 - 12x + (-12/2) ^ 2 = -15 + (-12/2) ^ 2

 Rewriting we have:
 x ^ 2 - 12x + (-6) ^ 2 = -15 + (-6) ^ 2

x ^ 2 - 12x + 36 = -15 + 36
 
(x-6) ^ 2 = 21
 x-6 =+/- \sqrt{21}
 Therefore, the solutions are:
 x = 6 - \sqrt{21}
 x = 6 + \sqrt{21}
 Answer:
 
the solution set of the equation is:
 
x = 6 - \sqrt{21}
 x = 6 + \sqrt{21}
3 0
3 years ago
Read 2 more answers
Given two concentric circles (circles that have the same center point), with the inner circle having a radius of 1 r and the out
Leno4ka [110]

Answer:

(x, y) ⇒ (2x, 2y)

Step-by-step explanation:

Transformation is the movement of a point from its initial location to a new location. Types of transformation are reflection, translation, rotation and dilation.

Dilation is the increase or decrease in size of a figure. If a figure with point A(x, y) is dilated by a scale factor of k, the new location is at A'(kx, ky). If k > 1, it is an enlargement and if k < 1, it is a reduction.

Given that the inner circle has a radius of 1 r and the outer one has a radius of 2 r. To map the inner circle onto the outer circle, the inner circle would need to be enlarged. The scale factor is:

k = outer circle radius / inner circle radius = 2r / 1r = 2

A dilation with a scale factor of 2 would be needed to map the inner circle onto the outer circle.

That is:

(x, y) ⇒ (kx, ky)

8 0
3 years ago
What is the equation for trying to solve slope ?
Anit [1.1K]
Y = mx + b
i hope this helped !
8 0
3 years ago
Read 2 more answers
find the functions and their domains (enter the domains in interval notation.)f(x)= x + (1/x)g(x)= x + 17 / x+2(a) f o g
nikdorinn [45]

Answer:

f o g = \frac{(x+17)^2+(x+2)^2}{(x+2)*(x+17)}

(-∞; -17)∪(-17;-2)∪(-2;+∞)

Step-by-step explanation:

Calculate f o g is equal to do f(g(x)).

To calculate it, we need to replace each x in f(x) with g(x)= \frac{x+17}{x+2}.  

f(g(x)) = \frac{x+17}{x+2} + \frac{1}{\frac{x+17}{x+2}} =\\ \frac{x+17}{x+2} + \frac{x+2}{x+17} =\\ \frac{(x+17)*(x+17)+(x+2)*(x+2)}{(x+2)*(x+17)} =\\ \frac{(x+17)^2+(x+2)^2}{(x+2)*(x+17)}

f o g = \frac{(x+17)^2+(x+2)^2}{(x+2)*(x+17)}

The domain of f o g is the set of all real numbers x such that x is in the domain of the function g and g(x) is in the domain of the function f. The domain of g(x) is all the real numbers without -2 because the denominator can't be zero. And the domain of f(x) is all the real numbers without 0 for the same reason.

We need to see when g(x) = 0

g(x) = \frac{x+17}{x+2} = 0\\x + 17 = 0\\x = -17

Therefore, the domain of f o g is all the real numbers without -2 and -17.

Written as an interval is (-∞; -17)∪(-17;-2)∪(-2;+∞).

5 0
4 years ago
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