For this case we have the following polynomial:

The first thing to do is to place the variables on the same side of the equation.
We have then:

We complete the square by adding the term (b / 2) ^ 2 on both sides of the equation.
We have then:

Rewriting we have:

Therefore, the solutions are:
Answer:
the solution set of the equation is:
Answer:
(x, y) ⇒ (2x, 2y)
Step-by-step explanation:
Transformation is the movement of a point from its initial location to a new location. Types of transformation are reflection, translation, rotation and dilation.
Dilation is the increase or decrease in size of a figure. If a figure with point A(x, y) is dilated by a scale factor of k, the new location is at A'(kx, ky). If k > 1, it is an enlargement and if k < 1, it is a reduction.
Given that the inner circle has a radius of 1 r and the outer one has a radius of 2 r. To map the inner circle onto the outer circle, the inner circle would need to be enlarged. The scale factor is:
k = outer circle radius / inner circle radius = 2r / 1r = 2
A dilation with a scale factor of 2 would be needed to map the inner circle onto the outer circle.
That is:
(x, y) ⇒ (kx, ky)
Y = mx + b
i hope this helped !
Answer:
f o g = 
(-∞; -17)∪(-17;-2)∪(-2;+∞)
Step-by-step explanation:
Calculate f o g is equal to do f(g(x)).
To calculate it, we need to replace each x in f(x) with g(x)=
.

f o g = 
The domain of f o g is the set of all real numbers x such that x is in the domain of the function g and g(x) is in the domain of the function f. The domain of g(x) is all the real numbers without -2 because the denominator can't be zero. And the domain of f(x) is all the real numbers without 0 for the same reason.
We need to see when g(x) = 0

Therefore, the domain of f o g is all the real numbers without -2 and -17.
Written as an interval is (-∞; -17)∪(-17;-2)∪(-2;+∞).