The sums range from 2 to 12 of which 6 are even out of 11 possible sums.
There are 4 multiples of 3, two of which are odd.
So the number of even sums is 6 and there are 2 unique or odd multiples of 3.
So there are a total 6+2=8 outcomes we want out of 36 possible outcomes.
The probability is then 8/36 or 2/9
Answer:
80 m^2
Step-by-step explanation:
The formula is lwh/3. 5*6*8=240 240/3=80
Im not sure if i am understanding the question correctly...
If you are asking if Jama's mom is correct, then no. she is wrong. this is because
if you take the proportion, (is/of)=(%/100) you get (x/30)=(70/100). You then solve for x which in this case would be 21 students are wearing tennis shoes.
Hope this helps.
6z -4 - z + 10 = -9
Combine like terms
5z + 6 = -9
Subtract both sides by 6
5z = -15
Divide both sides by 5
z = -3
Have an awesome day! :)
