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1 year ago

A ball is kicked upward with an initial velocity of 52 feet per second. The ball's height, h (in feet), from the ground Is

Mathematics

1 answer:

Norma-Jean [14]1 year ago

5 0

Check the picture below.

$\textit{vertex of a vertical parabola, using coefficients} \\\\ h(t)=\stackrel{\stackrel{a}{\downarrow }}{-16}t^2\stackrel{\stackrel{b}{\downarrow }}{+52}t\stackrel{\stackrel{c}{\downarrow }}{+0} \qquad \qquad \left(-\cfrac{ b}{2 a}~~~~ ,~~~~ c-\cfrac{ b^2}{4 a}\right) \\\\\\ \left(-\cfrac{ 52}{2(-16)}~~~~ ,~~~~ 0-\cfrac{ (52)^2}{4(-16)}\right) \implies \left( - \cfrac{ 52 }{ -32 }~~,~~0 - \cfrac{ 2704 }{ -64 } \right)$

$\left( \cfrac{13}{8}~~,~~\cfrac{169}{4} \right)\implies \underset{\stackrel{\uparrow \hspace{3em}}{seconds\qquad }}{\stackrel{\stackrel{\qquad feet}{\hspace{3em}\downarrow }}{\left( 1\frac{5}{8}~~,~~42\frac{1}{4} \right)}}$

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Solve the equation 2x-11=k for x

Lilit [14]

x = k/2 + 11/2

Step-by-step explanation:

$\frac{k}{2} + \frac{11}{2} = \frac{k+11}{2}$

hope this helped :)

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2 years ago

The larger of two numbers is 10 less than twice the smaller number. if the sum of the two numbers is 38, find the tqo nubers

Iteru [2.4K]

Let two number A and B, and A >B

as we know A+10=2B① && A+B =38②

①-② solve that
B=16 so A=22

so, they are 16 and 22

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2 years ago

An odd number between 301 and 370 has three different digits. If the sum of its digits is five times the hundreds digit, find th

damaskus [11]

For the answer to the question above, <span>
5x3 (the hundreds digit)= 15
so 3+x+y=15. 15-3=12. x+y=12.
No even number + odd number can be = 12, so both digits must be odd.
That leaves us with 3+3+z=15, 3+3+x =15 and 3+5+y= 15. 3+1+9 (highest odd digit)= 13 so that is wrong.
3+3+9= 15, but there is a double digit, so wrong again. 3+5+7=15. 357 is the answer.</span>

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2 years ago

X=4y,2x+y=18 solve by substitution show all work

Mkey [24]

Here is the math, did it on paper, sorry it’s blue. just add parenthesis around the x in the second equation and add what x equals. then solve as PEMDAS.

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1 year ago

The probability of event a is x, and the probability of event b is y. if the two events are independent, which condition must be

nalin [4]

Condition (A) P(B/A) = y is true.

<h3>What is probability?</h3>

Probability is an area of mathematics that deals with numerical descriptions of how probable an event is to occur or how likely a statement is to be true.

To find the true condition:

If two events are independent, then:

Pr(A∩B) = Pr(A) . Pr(B)

Use formulas for conditional probabilities:

Pr(A/B) = Pr(A∩B) / Pr(B)
Pr(B/A) = Pr(B∩A) / Pr(A)

For independent events these formulas will be:

Pr(A/B) = Pr(A∩B) / Pr(B) = Pr(A) . Pr(B) / Pr(B) = Pr(A)
Pr(B/A) = Pr(B∩A) / Pr(A) = Pr(B) . Pr(A) / Pr(A) = Pr(B)

Now in your case, Pr(A) = x and Pr(B) = y.

Pr(A/B) = x, Pr(B/A) = y, Pr(A∩B) = x.y

Therefore, condition (A) P(B/A) = y is true.

Know more about probability here:

brainly.com/question/25870256

#SPJ4

The complete question is given below:

The probability of event A is x, and the probability of event B is y. If the two events are independent, which of these conditions must be true?

a. P(B|A) = y

b. P(A|B) = y

c. P(B|A) = x

d. P(A and B) = x + y

e. P(A and B) = x/y

5 0

1 year ago