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2 years ago

−2x=x^2 minus 6, Rewrite the equation by completing the square. please answer

Mathematics

1 answer:

Paul [167]2 years ago

4 0

Answer:

$(x+1)^{2} -5$

Step-by-step explanation:

$-2x=x^{2} -6 \\x^{2} +2x-6\\(\frac{b}{2}) ^{2} =(\frac{2}{2}) ^{2} =1^{2} =1\\so, (x^{2} +2x+1)-6+1\\ x^{2} +2x+1=(x+1)^{2} \\-6+1=5\\(x+1)^{2} -5$

Sorry it took so long

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The cost for hiring a car for 2 days in 2018 was Rs. 264 which was 20% more than in 2013. What was the cost of hiring a car for

Goshia [24]

The cost of hiring a car for 2 days in 2013 is Rs. 316.8

<h3>How to find the cost of hiring in 2013 ?</h3>

The cost for hiring a car for 2 days in 2018 was Rs. 264 which was 20% more than in 2013.

Therefore,

cost of hiring for 2018 = Rs. 264

Therefore,

let

cost of hiring in 2013 = 20%(264) + 264

cost of hiring in 2013 = 20 / 100 × 264 + 264

cost of hiring in 2013 = 1 / 5 × 264 + 264

cost of hiring in 2013 = 264 / 5 + 264

cost of hiring in 2013 = 52.8 + 264

cost of hiring in 2013 = 316.8

Therefore, the cost of hiring a car for 2 days in 2013 is Rs. 316.8.

learn more on cost here: brainly.com/question/1663590

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2 years ago

2) Complete the table.<br>x<br>20<br>200<br>2000<br>15<br>20

Dimas [21]

I think it’s 25 but I’m not too sure

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2 years ago

Suppose that 35 people are divided in a random manner into two teams in such a way that one team contains 10 people and the othe

Effectus [21]

Answer:

0.5798 or 57.98%

Step-by-step explanation:

The total number of ways to form the two teams is the combination of choosing 10 people out of 35 (₃₅C₁₀). The number of possibilities that A and B are both on the 10-people team is given by the combination of choosing 8 people (since two are fixed) out of 33 (₃₃C₈).The number of possibilities that A and B are both on the 25-people team is given by the combination of choosing 10 people out of 33 (₃₃C₈).

Therefore, the probability that two particular people A and B will be on the same team is:

$P = \frac{_{33}C_8+_{33}C_{10}}{_{35}C_{10}} \\\\P=\frac{\frac{33!}{(33-8)!8!}+\frac{33!}{(33-10)!10!} }{\frac{35!}{(35-10)!10!}} \\\\P=\frac{69}{119} = 0.5798$

The probability is 0.5798 or 57.98%.

8 0

2 years ago

So here's the question

Lesechka [4]

Yes, is subtraction, to get their "difference".

first off, let's convert the mixed fractions, to "improper", and then subtract.

$\bf \stackrel{red~yarn}{9\frac{1}{5}}-\stackrel{blue~yarn}{3\frac{11}{25}}$

$\bf -------------------------------\\\\
\stackrel{mixed}{9\frac{1}{5}}\implies \cfrac{9\cdot 5+1}{5}\implies \stackrel{improper}{\cfrac{46}{5}}
\\\\\\
\stackrel{mixed}{3\frac{11}{25}}\implies \cfrac{3\cdot 25+11}{25}\implies \stackrel{improper}{\cfrac{86}{25}}\\\\
-------------------------------\\\\
\cfrac{46}{5}-\cfrac{86}{25}\impliedby \textit{our LCD is 25}\implies \cfrac{(5\cdot 46)~~-~~(1\cdot 86)}{25}
\\\\\\
\cfrac{230~-~86}{25}\implies \cfrac{144}{25}\implies 5\frac{19}{25}$

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3 years ago

Lin’s road trip is 75 miles long. She has completed 20% of a trip so far. How many miles has Lin gone so far?

Lynna [10]

You're basically told that Lin has traveled 20% of 75. Since 20% is one fifth, she has traveled 75/5=15 miles so far.

7 0

2 years ago