one correct answer is g(x)=0.
g'(4)=0 and g'(-8)=0
A 0 will make the right decision
Answer:
6
Step-by-step explanation:
JM is 6 riiite
and JMN should be an equilateral triangle so
The answer is <span>a.)(x - 4)2 = 3.
(x - a)</span>² = b can be expressed as:
x² - 2ax + a² = b ⇒ x² - 2ax + a² - b = 0
Our equation is x² - 8x + 13 = 0.
The general formula is x² - 2ax + (a² - b) = 0
Thus:
8x = 2ax and a² - b = 13
Divide both sides of the first equation (8x = 2ax) by x:
8 = 2a ⇒ a = 8 ÷ 2 = 4
Replace a in the second equation (a² - b = 13):
4² - b = 13 ⇒ b = 4² - 13 = 16 - 13 = 3
Now when we have a and b, let's just replace them in the general equation:
(x - a)² = b
(x - 4)² = 3
The maximum height the ball achieves before landing is 682.276 meters at t = 0.
<h3>What are maxima and minima?</h3>
Maxima and minima of a function are the extreme within the range, in other words, the maximum value of a function at a certain point is called maxima and the minimum value of a function at a certain point is called minima.
We have a function:
h(t) = -4.9t² + 682.276
Which represents the ball's height h at time t seconds.
To find the maximum height first find the first derivative of the function and equate it to zero
h'(t) = -9.8t = 0
t = 0
Find second derivative:
h''(t) = -9.8
At t = 0; h''(0) < 0 which means at t = 0 the function will be maximum.
Maximum height at t = 0:
h(0) = 682.276 meters
Thus, the maximum height the ball achieves before landing is 682.276 meters at t = 0.
Learn more about the maxima and minima here:
brainly.com/question/6422517
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