Using linear pairs,

By the exterior angle theorem,

25 is the length of x, using the 30-60-90 special triangle method
Answer:
Hence, the average rate of change is:

Step-by-step explanation:
We are asked to calculate the average value of the function:
in 2 ≤ x ≤ 6
The average rate of change of the function f(x) in the interval 2 ≤ x ≤ 6 is given as:

Now,


Hence, the average rate of change is:

Hence, the average rate of change is:

Answer:6.0, 130
Step-by-step explanation:
Just got the question right on edgenuity.
Answer:
4951 students
Step-by-step explanation:
If there was 99 students from each state, that would make the total to be:
99 * 50 = 4950
We can use the pigeon hole principle to make this the minimum number required.
The pigeon hole principle basically tells us that if you have more "pigeons" than "holes" then there must be one hole with multiple objects in it.
So, using this idea, we see that:
we need at least 1 more to ensure this
So, min number required would be
4950 + 1 = 4951