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gavmur [86]
3 years ago
12

Simplify (-5)^5 over (-5)^-6

Mathematics
1 answer:
xxMikexx [17]3 years ago
5 0

Answer:

− 48828125

Step-by-step explanation:

you can use a calculator for algebra

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Frank started the summer with $60 in his account. He
Otrada [13]

Answer:

The answer should be 12

Step-by-step explanation

he has 60 in his account already so add 35 and 15 (60+35+15=110) then add 48+24+50 which equals 122. Now subtract 110-122 and you'll get 12. so the answer is 12.

7 0
3 years ago
Find the number that makes the ratio equivalent to 2:3.<br> 24: BLANK
Vitek1552 [10]

Answer:

equivalent ratio for this question is

4:6:48

5 0
2 years ago
Read 2 more answers
Im give 15 points if you know this phm
pickupchik [31]

Answer:

The answer is option (D) 8.17 × 10^8...

Hope u like it

8 0
3 years ago
4. Using the geometric sum formulas, evaluate each of the following sums and express your answer in Cartesian form.
nikitadnepr [17]

Answer:

\sum_{n=0}^9cos(\frac{\pi n}{2})=1

\sum_{k=0}^{N-1}e^{\frac{i2\pi kk}{2}}=0

\sum_{n=0}^\infty (\frac{1}{2})^n cos(\frac{\pi n}{2})=\frac{1}{2}

Step-by-step explanation:

\sum_{n=0}^9cos(\frac{\pi n}{2})=\frac{1}{2}(\sum_{n=0}^9 (e^{\frac{i\pi n}{2}}+ e^{\frac{i\pi n}{2}}))

=\frac{1}{2}(\frac{1-e^{\frac{10i\pi}{2}}}{1-e^{\frac{i\pi}{2}}}+\frac{1-e^{-\frac{10i\pi}{2}}}{1-e^{-\frac{i\pi}{2}}})

=\frac{1}{2}(\frac{1+1}{1-i}+\frac{1+1}{1+i})=1

2nd

\sum_{k=0}^{N-1}e^{\frac{i2\pi kk}{2}}=\frac{1-e^{\frac{i2\pi N}{N}}}{1-e^{\frac{i2\pi}{N}}}

=\frac{1-1}{1-e^{\frac{i2\pi}{N}}}=0

3th

\sum_{n=0}^\infty (\frac{1}{2})^n cos(\frac{\pi n}{2})==\frac{1}{2}(\sum_{n=0}^\infty ((\frac{e^{\frac{i\pi n}{2}}}{2})^n+ (\frac{e^{-\frac{i\pi n}{2}}}{2})^n))

=\frac{1}{2}(\frac{1-0}{1-i}+\frac{1-0}{1+i})=\frac{1}{2}

What we use?

We use that

e^{i\pi n}=cos(\pi n)+i sin(\pi n)

and

\sum_{n=0}^k r^k=\frac{1-r^{k+1}}{1-r}

6 0
3 years ago
The pirce of an item yesterday was$125 . Today, the price fell to 75. Find the percentage decrease.
Julli [10]

Answer:

Im sure the answer is 40%

<em>GL Deary</em>

<em>Hope I helped!!!</em>

<em><3</em>

8 0
4 years ago
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