All categories

3 years ago

Which regular polygon can be used to form a tessellation?

2 answers:

8 0

Theres only 3 shapes that can form such regualr tessellations triangle square and regular hexagon so that being said triangle is your answer

Westkost [7]3 years ago

6 0

<h2>Answer:</h2>

The regular polygon that could be used for tessellation is:

Triangle.

<h2>Step-by-step explanation:</h2>

Tessellation is a geometry that is formed by a repeating pattern of same shape without any gaps.

We can use only three regular polygon for the formation of Tessellation:

1) Equilateral Triangle

2) Square

3) Regular Hexagon.

Hence, from the given option the regular polygon that can be used to form a tessellation is:

Triangle.

You might be interested in

Marianna [84]

The expression into a single logarithm is $log[(x)^{10}][(2)^{30}]$

Step-by-step explanation:

Let us revise some logarithmic rules

$log(a)^{n}=nlog(a)$
$log(ab)=log(a)+log(b)$
$nlog(a)+mlog(b)=log[(a)^{n}][(b)^{m}]$

∵ 10 log(x) + 5 log(64)

- At first re-write 10 log(x)

∴ 10 log(x) = $log(x)^{10}$

- Then re-write 5 log(64)

∴ 5 log(64) = $log(64)^{5}$

∴ 10 log(x) + 5 log(64) = $log(x)^{10}$ + $log(64)^{5}$

- Use the 3rd rule above to make it single logarithm

∵ $log(x)^{10}$ + $log(64)^{5}$ = $log[(x)^{10}][(64)^{5}]$

∴ 10 log(x) + 5 log(64) = $log[(x)^{10}][(64)^{5}]$

∵ 64 = 2 × 2 × 2 × 2 × 2 × 2

∴ We can write 64 as $2^{6}$

∴ $(64)^{5}=(2^{6})^{5}$

- Multiply the two powers of 2

∴ $(64)^{5}=(2)^{30}$

∴ 10 log(x) + 5 log(64) = $log[(x)^{10}][(2)^{30}]$

The expression into a single logarithm is $log[(x)^{10}][(2)^{30}]$

Learn more:

You can learn more about the logarithmic functions in brainly.com/question/11921476

#LearnwithBrainly

6 0

3 years ago

Point D is the centroid of Triangle ABC. Find CD and CE.<br> DE = 9

sukhopar [10]

Given:

Point D is the centroid of Triangle ABC and DE = 9.

To find:

The measures of CD and CE.

Solution:

We know that, centroid is the intersection of medians and it divides each median in 2:1.

In triangle ABC, CE is a meaning and centroid D divided CE in 2:1. So,

Let the measures of CD and DE are 2x and x respectively.

DE = 9 (Given)

$x=9$

Now,

$CD=2x$

$CD=2(9)$

$CD=18$

And,

$CE=CD+DE$

$CE=18+9$

$CE=27$

Therefore, the measure of CD is 18 units and the measure of CE is 27 units.

6 0

3 years ago

Y=2/3x+1 , what is a order pair for this function?

zimovet [89]

To make this table, pick any value you want for x, then substitute it an solve for y.

For example, if you choose x=1, then
y=-2/3(1)-1
y=-2/3-3/3
y=-5/3

To do a three part table quickly, I like to use -1, 0, and 1 for the value of x, since -1 and 1 will not change the values, only the sign for -1, and 0 eliminates the m section of the equation.

I hope this helps !!!!

5 0

3 years ago

What is the perimeter in square units of the rectangle shown on the coordinate grid?

Rashid [163]

In order to find the Perimeter of the Rectangle, First we need to find the Length and Width of the Rectangle.

Distance between two points (x₁ , y₁) and (x₂ , y₂) is given by :

$\bigstar\;\; \mathsf{Distance = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}}$

There are two lengths in a rectangle. Let us find any one length of the rectangle.

I'm considering the length with co-ordinates (-8 , 2) and (-2 , 10)

Here : x₁ = -8 and x₂ = -2 and y₁ = 2 and y₂ = 10

Substituting the values in the distance formula, We get :

$\mathsf{\implies Length = \sqrt{[-2 - (-8)]^2 + [10 - 2]^2}}$

$\mathsf{\implies Length = \sqrt{[-2 + 8]^2 + [8]^2}}$

$\mathsf{\implies Length = \sqrt{[6]^2 + [8]^2}}$

$\mathsf{\implies Length = \sqrt{36 + 64}}$

$\mathsf{\implies Length = \sqrt{100}}$

$\mathsf{\implies Length = 10}$

There are two widths in a rectangle. Let us find any one width of the rectangle.

I'm considering the width with co-ordinates (-2 , 10) and (2 , 7)

Here : x₁ = -2 and x₂ = 2 and y₁ = 10 and y₂ = 7

Substituting the values in the distance formula, We get :

$\mathsf{\implies Width = \sqrt{[2 - (-2)]^2 + [7 - 10]^2}}$

$\mathsf{\implies Width = \sqrt{[2 + 2]^2 + [-3]^2}}$

$\mathsf{\implies Width = \sqrt{[4]^2 + [-3]^2}}$

$\mathsf{\implies Width = \sqrt{16 + 9}}$

$\mathsf{\implies Width = \sqrt{25}}$

$\mathsf{\implies Width = 5}$

Perimeter of a Rectangle is given by : 2[Length + Width]

$:\implies$ Perimeter of the given rectangle = 2[10 + 5]

$:\implies$ Perimeter of the given rectangle = 2[15]

$:\implies$ Perimeter of the given rectangle = 30

<u>Answer</u> : Perimeter of the given rectangle is 30 square units

4 0

3 years ago

Read 2 more answers

Mr.Muckworth earned $26,450 last year. He worked an average of 7.5 hours a day for 236 days. How much did he earn for each hour

Vsevolod [243]

You would multiply 236 days by 7.5 hours each day then divide that by 26,450 because that's the overall amount you would get 14.94350
That rounded to the nearest cent would be $14.94,per hour

5 0

4 years ago