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Zielflug [23.3K]
3 years ago
11

A ____ can only display numerical data , while a ______ can display categorical data?

Mathematics
1 answer:
zlopas [31]3 years ago
4 0

Option B

Histogram shows quantitative data. Histograms are used to show the distribution of numerical data. In histogram , the bars are continuous that is adjacent to each other so it is used to represent numerical data.

Bar graphs always shows qualitative data. Bar graph describes the type of categories being compared. There are gaps between the bars. So Bar graphs are used to display categorical data.

A histogram can only display numerical data , while a bar graph can display categorical data

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If sin theta = 2/7 and tan theta>0 what is the value of cos theta
Ronch [10]

Answer:

Step-by-step explanation:

sin(θ) = 2/7

sin²(θ) +cos²(θ) =1

(\frac{2}{7})^{2} +cos^2(theta)=1 \\\\cos^2(theta)=1-(\frac{4}{49} )=\frac{49}{49}-\frac{4}{49} =\frac{45}{49} \\ \\cos(theta)=+/-\sqrt{\frac{45}{49} } =+/-\frac{3\sqrt{5} }{7}

Answer \\ is \frac{3\sqrt{5} }{7}

Answer is positive because tangent is positive, sin is also positive, and tan=sin/cos.

6 0
3 years ago
1. Find two functions f(x) and g(x) such that f[g(x)] = x but g[f(x)] does not equal x.2. State the vertical, horizontal asympto
Harman [31]

Answer:

1. f(x)=x^{2} and g(x)=-\sqrt{x}

2. Vertical Asymptote: x=-4

    Horizontal Asymptote: y=1

    Zeros: (-2,0)

    Because the graph will have a hole at x=-1. This is, the graph is not defined for that particular x-value.

3.  f(x)=x^{2}+4

It has two complex roots, so there is no place in the graph where it crosses the x-axis.

Step-by-step explanation:

1. If we find the composite function f[g(x)] with the functions:

f(x)=x^{2} and g(x)=-x, we will get the following:

f[g(x)]=(-\sqrt{x})^{2}

which simplifies to

f[g(x)]=x

on the other hand, if we find g[f(x)] we will get the following:

g[f(x)]=-\sqrt{x^2}

which simplifies to:

g[f(x)]=-x

2.

Before finding the asymptotes, it's a good idea to factor both the numerator and denominator of the function, so we get:

f(x)=\frac{x^{2}+3x+2}{x^{2}+5x+4}

f(x)=\frac{(x+2)(x+1)}{(x+4)(x+1)}

we can now see that this function can be simplified. It is important to simplify this function so we don't confuse vertical asymptotes with holes in the graph, so when simplifying we get the following:

f(x)=\frac{x+2}{x+4}

now we can set the denominator equal to zero.

x+4=0

and solve for x:

x=-4 this is our vertical asymptote.

For the horizontal asymptote, there is a rule that tells us that if the polynomials on the numerator and denominator have the same degree (the same greatest power), then the horizontal asymptote is found by dividing the lead coefficient of the polynomial on the numerator by the lead coefficient on the denominator. In this case the lead coefficients are 1 and 1 so the horizontal asymptote is:

y=\frac{1}{1}

so the horizontal asymptote is at:

y=1.

The zeros of the function are located at the x-values that will turn the numerator of the simplified fraction equal to zero, so we get:

x+2=0

x=-2

so the only zero will be located at (-2,0)

x=-1 is not a zero because the original function is not defined for x=-1, there is a hole in the graph at this x-value.

Take a look at the graph of the function (See attached picture)

3.

This will happen when there are no real zeros. Take for example the function:

f(x)=x^{2}+4

In this case this problem has 2 non-real zeros:

x^{2}+4=0

x^{2}=-4

x=\sqrt{-4}

so:

x=2i   or   x=-2i

since they are complex numbers they cannot be graphed on a coordinate axis, so the graph will not cross the x-axis. See attached picture.

6 0
3 years ago
Can somone help me with this​
SpyIntel [72]

Answer:

(4,-6)

Step-by-step explanation:

2x + 2y = -20

x + y = -10

y = -x-10

5x-5y = -10

x-y=-2

x-(-x-10) = -2

2x-10 = -2

2x= 8

x = 4

4 + y = -10

y = -6

4 0
3 years ago
Write an equation in slope-intercept form for the line perpendicular to y = x + 5 that passes through the point (–9, 5).
Zolol [24]

Answer:

Step-by-step explanation:

perp.: -1

y - 5 = -1(x + 9)

y - 5 = -x - 9

y = -x - 4

8 0
3 years ago
A regular hexagon is inscribed in a circle and another regular hexagon is circumscribed about the same circle. What is the ratio
Anna007 [38]

4/3 of the area of the larger hexagon to the area of the smaller hexagon

Let the sides of the interior hexagon be 2 cm long, then this hexagon is made up of 6 equilateral triangles of side = 2.

The area of this hexagon = 6 * 1 * sqrt3 = 6 sqrt3 ( as the triangle is made up of 2 60-30-90 triangles)

The exterior hexagon is made up of 6 equilateral triangles with altitude 2 and the area = 6 * 2 * (2 / sqrt3 ) = 24 / sqrt3

area exterior hex / interior hex = 24 / sqrt3 * 1 / 6sqrt3 = 24/18

= 4/3

Required ratio = 4/3 answer

Learn more about Equations:

brainly.com/question/16450098

#SPJ4

3 0
2 years ago
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