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Zielflug [23.3K]
3 years ago
11

A ____ can only display numerical data , while a ______ can display categorical data?

Mathematics
1 answer:
zlopas [31]3 years ago
4 0

Option B

Histogram shows quantitative data. Histograms are used to show the distribution of numerical data. In histogram , the bars are continuous that is adjacent to each other so it is used to represent numerical data.

Bar graphs always shows qualitative data. Bar graph describes the type of categories being compared. There are gaps between the bars. So Bar graphs are used to display categorical data.

A histogram can only display numerical data , while a bar graph can display categorical data

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Using the method of completing the square, put each circle into the form
tatiyna

Answer:

Standard form: (x-\frac{1}{2})^2 + (y-0)^2 = 15

Center: (\frac{1}{2}, 0)

Radius: r =\sqrt{15}

Step-by-step explanation:

The equation of a circle in the standard form is

(x-h)^{2} + (y-k)^{2} = r^{2}

Where the point (h, k) is the center of the circle

To transform this equation 4x^{2} -4x + 4y^{2} - 59 = 0 this equation  in the standard form we use the method of square.

First, we group similar variables

(4x^{2} -4x) + (4y^{2}) - 59 = 0

Divide both sides of equality by 4

(x^{2} -x) + (y^{2}) - 14.75 = 0

Now we complete square for variable x.

Take the coefficient "b" that accompanies the variable x and divide by 2. Then, elevate the result to the square:

b =-1\\\\\frac{b}{2}= \frac{-1}{2}= -\frac{1}{2}\\\\(\frac{b}{2})^2=  (-\frac{1}{2})^2 = \frac{1}{4}

Now add (\frac{b}{2})^2 on both sides of the equality

(x^{2} -x +\frac{1}{4}) + (y^{2}) - 14.75 = (\frac{1}{4})

Factor the expression and simplify the independent terms

(x-\frac{1}{2})^2 + (y^{2}) = 15

(x-\frac{1}{2})^2 + (y-0)^2 = 15

Then

h =\frac{1}{2}\\\\k=0

and the center is (\frac{1}{2}, 0)

radius r =\sqrt{15}

3 0
3 years ago
Can someone help me with problem?
Dennis_Churaev [7]
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7 0
3 years ago
The quotient of a number and 7 is 32
ella [17]

Answer:

=99=99=99=99=78

Step-by-step explanation:

6 0
3 years ago
Can you please find the mean median mode and range for these two tables?( separate answers for the two)
Fudgin [204]

Answer:

For the Chinese students the mean is 6.8 and the median is 7. The mode is 6 and the range is 5.

Step-by-step explanation:

The mean is just the Sum of all the number on the left columns divided by the number students. The sum is 204 and there are 30 students. So divide 204 by 30 and you get 6.8.

To find the median for Chinese students, all you need to do is arrange the numbers from least to greatest and then find the number,or numbers, that are left in the middle. So you cross off numbers on both ends until you get to the middle. Ex: you are given the numbers 12,7, and 5. Arrange them like so, 5, 7, 12. cross off the numbers on the sides and you get 7 as your median. Because 30 is divisible by 2, you end up with two numbers in the middle. When that happens, you add both middle numbers together and then divide by 2.  

Finding the mode shouldn't be too hard if you've arranged the numbers from least to greatest. The mode is just the number you see most often in a set of data. In this case, 6 is the most common number of letters a Chinese student has.

Lastly, to find the range, you need to find the lowest value or number and subtract it from the highest value or number. Here the highest value is 9 and the lowest is 4. So 9 - 4 = 5.

6 0
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Write the standard form of the line with the given information. Include your work in your final answer. Type your answer in the
photoshop1234 [79]

Answer:

y=3x-2

Step-by-step explanation:

y=mx+b

m=slope and b=y-intercept

7 0
3 years ago
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