Answer:
D. 1K
Explanation:
The address space 0x0000-0x3FF is of 1KB(One Kilo Byte) since 0x3ff is equal to 1023. therefore 1023=1 KB.
bitwise 0x3ff zeros out the top bits of the number such that the result is always between 0 and 1023. It is essentially the same thing as modulo( num,1024) for positive values of num.
Hence the answer is D 1K
import random
rock,paper,scissors = 1,2,3
choice = int(input("Please choose 1 2 or 3: "))
computer = random.randint(1,3)
player_won = False
draw = False
if choice == computer:
draw = True
elif choice == 1 and computer == 3:
player_won = True
elif choice == 2 and computer == 1:
player_won = True
elif choice == 3 and computer == 2:
player_won = True
if player_won:
print("You won!")
elif not player_won and not draw:
print("The computer won!")
else:
print("It's a draw!")
First, I recommend importing at the beginning of your program. Also, you can combine all your same datatype variables in one line. You also need to cast your user choice to an integer so you can compare it with the computer's choice. I wrote the if, elif, and else statements using a boolean variable. I simply wrote all the possibilities that would result in the player winning and this would result in the player_won variable being true. If this is the case, we print to the console, "You won!"
Explanation:
didn't evaluation into question
Cleaning up a system helps clear up the space on the drives. It may also clear up processor usage, ram usage if you uninstall programs that automatically started when the system booted. You may also delete some unwanted programs in the process.
