8y = -40
/8 /8 divide by 8 on both sides
y = -5
See how many times 30 fits into 383.
30 x 12 = 360, 30 x 13 = 390
therefore, 30 fits into 383 twelve times.
383 - 360 = 23
you'll have a remainder of 23
Answer:
rolling a number cube with sides labeled 1 through 6 and tossing a coin.
Step-by-step explanation:
We will resolve each statement to determine the events that has exactly 12 possible outcomes.
N = number of possible outcomes for a cube
Nc = number of possible outcomes for a coin
Nca = number of possible outcomes for the cards
i. rolling a number cube with sides labeled 1 through 6 and then rolling the number cube again
Nt = N × N
N = 6 ( cube has 6 possible outcomes and its rolled twice)
Nt = 6 × 6 = 36
ii. tossing a coin and randomly choosing one of 4 different cards.
Nt = Nc × Nca
Nc = 2 ( coin has two outcomes)
Nca = 4 ( 4 possible cards )
B = 2 × 4 = 8
iii. rolling a number cube with sides labeled 1 through 6 and tossing a coin.
N = N × Nc
N = 6 ( cube has 6 possible outcomes)
Nc = 2 (coin has two faces)
N = 6 × 2 = 12 (correct)
Iv. tossing a coin 6 times.
N = Nc^6
Nc = 2
N = 2^6 = 64
Therefore, the correct answer is iii.
rolling a number cube with sides labeled 1 through 6 and tossing a coin.
9×27+2×31-28= n
243+62-28=n
277=n
n=277
13 - (x+2) = 8
subtract 13 from both sides
-(x+2) = -5
divide by -1 to get rid of negative
(x+2) = 5
subtract 2 from both sides
x=3
