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Andre45 [30]
3 years ago
9

Help asap, best explained or best answer given will get brainliest :p​

Mathematics
2 answers:
dimaraw [331]3 years ago
5 0

Answer:

it will be 14x15x18+11+13+16

Sergio [31]3 years ago
5 0
Just a quick question is this map test ?? Because I took the same thing
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I NEED THE ANSWER ASAP PLEASE
horrorfan [7]

Answer:

7

Step-by-step explanation:

the answer would be 7 because if there is 2 in per hour just go 2,4,6,8,10,12

and then count all the numbers i did and that will be your answer (7)

7 0
3 years ago
A standard deck of cards contains 52 cards. one card is selected from the deck. ?(a) compute the probability of randomly selecti
Rama09 [41]
Let
P(h)= probability of selecting heart = 13/52= 1/4
similarly
P(s)= probability of selecting spade =1/4
P(c)= probability of selecting club =1/4
P(d)= probability of selecting diamond =1/4

a)

P(h or s)= P(h)+P(s)= 1/4+1/4=2/4=1/2=0.5

b)

P(h or s or c)=P(h)+P(s)+P(c)=1/4+1/4+1/4=3/4=0.75

c) 

P(2 or a diamond)=n(2heart, 2spade,2club,13 diamonds)/total number of cards

=(1+1+1+13)/52=16/52=4/13=0.3

or we could solve it as follows:

P(2 or a diamond)=P(2)+P(diamond)-P(2diamond)=4/52  +  13/52  + 1/52  = (4+13-1)/52=16/52=0.3
3 0
3 years ago
Petra is asked to color 6/6 of her grid. she must use 3 colors; blue read and pink. there must be more blue sections than red se
Mandarinka [93]
1. 3 blues, 2 red, 1 pink.
2. 3 blues, 2 pink, 2 red.
3. 4 blues, 1 red, 1 pink.

3 0
4 years ago
Scott and Letitia are brother and sister. After dinner, they have to do the dishes, with one washing and the other drying. They
ehidna [41]

Answer:

The probability that Scott will wash is 2.5

Step-by-step explanation:

Given

Let the events be: P = Purple and G = Green

P = 2

G = 3

Required

The probability of Scott washing the dishes

If Scott washes the dishes, then it means he picks two spoons of the same color handle.

So, we have to calculate the probability of picking the same handle. i.e.

P(Same) = P(G_1\ and\ G_2) + P(P_1\ and\ P_2)

This gives:

P(G_1\ and\ G_2) = P(G_1) * P(G_2)

P(G_1\ and\ G_2) = \frac{n(G)}{Total} * \frac{n(G)-1}{Total - 1}

P(G_1\ and\ G_2) = \frac{3}{5} * \frac{3-1}{5- 1}

P(G_1\ and\ G_2) = \frac{3}{5} * \frac{2}{4}

P(G_1\ and\ G_2) = \frac{3}{10}

P(P_1\ and\ P_2) = P(P_1) * P(P_2)

P(P_1\ and\ P_2) = \frac{n(P)}{Total} * \frac{n(P)-1}{Total - 1}

P(P_1\ and\ P_2) = \frac{2}{5} * \frac{2-1}{5- 1}

P(P_1\ and\ P_2) = \frac{2}{5} * \frac{1}{4}

P(P_1\ and\ P_2) = \frac{1}{10}

<em>Note that: 1 is subtracted because it is a probability without replacement</em>

So, we have:

P(Same) = P(G_1\ and\ G_2) + P(P_1\ and\ P_2)

P(Same) = \frac{3}{10} + \frac{1}{10}

P(Same) = \frac{3+1}{10}

P(Same) = \frac{4}{10}

P(Same) = \frac{2}{5}

8 0
3 years ago
Max and Leah each have a lemonade stand . Max sold 12 glasses the first hour and 10 glasses each hour after that . Leah sold 8 g
djverab [1.8K]

Answer:

120

Step-by-step explanation:

8 0
4 years ago
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