Given formula : formula t = −0.0035a + g, where t is the atmospheric temperature in degrees Fahrenheit, a is the altitude in feet and g is the ground temperature in degrees Fahrenheit.

To find: 1) If the atmospheric temperature is −25.4 °F and the ground temperature is 60°F, what is the altitude?

2) The equation for a is a = .

Solution: 1) We have atmospheric temperature(t) =−25.4 °F, and

ground temperature(g) =60°F.

Plugging values of t and g in given formula t = −0.0035a + g, we get

-25.4 = −0.0035a + 60.

Subtracting 60 from both sides, we get

-25.4 - 60 = −0.0035a + 60-60

-85.4 = −0.0035a.

Dividing both sides by -0.0035, we get

-85.4/-0.0035 = −0.0035a/-0.0035.

24400 = a

Therefore, if the atmospheric temperature is −25.4 °F and the ground temperature is 60°F, the altitude is 24400 feet.

2) We need to solve equation for a in this part.

We have

t = −0.0035a + g

Subtracting g from both sides, we get

t -g = −0.0035a + g-g

t-g = −0.0035a

Dividing both sides by −0.0035, we get

(t-g)/-0.0035 = −0.0035a/-0.0035

$a=-\frac{t-g}{0.0035}$

Distributing minus sign on the top, we get

$a=\frac{g-t}{0.0035}$ .

Therefore, the equation for a is a =(g-t)/0.0035.

4 0

2 years ago

What is the product of (x+1) and (2x^2+3x-1)?

Assoli18 [71]

(x + 1)(2x^2 + 3x - 1) : Can be solved in multiple ways but easiest for me :P

x (2x^2 + 3x - 1) + 1(2x^2 + 3x - 1)

(2x^3 + 3x^2 - x) + (2x^2 + 3x - 1)

2x^3 + 5x^2 + 2x - 1

3 0

2 years ago