In ΔTUV, the measure of ∠V=90°, the measure of ∠T=11°, and TU = 30feet. Find the length of UV to the nearest tenth of a foot.

A large box is packed with 6 rows of 8 boxes of dried cranberries in the bottom layer. The box is about 4 layers high. Estimate

Salsk061 [2.6K]

Answer:

Step-by-step explanation:

The estemit will be 0

5 0

3 years ago

Someone please help me with this and explain it please.

Yuki888 [10]

<h3>Answer: Choice D) $\sqrt{34}, 6, 2\pi, \sqrt{42}$ </h3>

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Explanation:

Use a calculator to find the decimal form of each of the following below (values are approximate; rounded to 2 decimal places)

2pi = 6.28
sqrt(42) = 6.48
sqrt(34) = 5.83

We see that the order of the decimal values is: 5.83, 6, 6.28, 6.48

So the order of the terms, from smallest to largest, is $\sqrt{34}, 6, 2\pi, \sqrt{42}$

5 0

3 years ago

I need #14 done by tomorrow around 9-10:00. Thank you so much if you do. God bless you :3

Vinvika [58]

Answer:

A) $\frac{1}{5}$

B) - 5

C) Not Possible

D) 5

E) $\frac{-1}{5}$

Step-by-step explanation:

All integers are rational numbers. But not all rational numbers are integers.

All whole numbers are integers. But not all integers are whole numbers.

I am a rational number but not an integer. Located on the right of 0.

This means that it should be a positive number. Since, it is a rational number but not an integer, it should be of the form $\frac{p}{q}$ .

From, the options $\frac{1}{5}$ would fit this description.

I am a rational number and an integer but not a whole number.

This means that it should be a negative integer. Since, all positive integers and zero would be whole numbers. From the options, the answer would be -5.

I am a whole number but not an integer.

This is clearly not possible because all whole numbers are a subset of integers.

I am a rational number, a whole number and an integer.

This means it is a positive integer. 5 would fit this description.

I am a rational number but not an integer; located on the left side of 0.

This means it is a negative number. $-\frac{1}{5}$ should be the answer.

3 0

3 years ago

Inverse laplace of [(1/s^2)-(48/s^5)]

Katen [24]

**Refresh page if you see [ tex ]**

I am not familiar with Laplace transforms, so my explanation probably won't help, but given that for two Laplace transform $F(s)$ and $G(s)$ , then $\mathcal{L}^{-1}\{aF(s)+bG(s)\} = a\mathcal{L}^{-1}\{F(s)\}+b\mathcal{L}^{-1}\{G(s)\}$

Given that $\dfrac{1}{s^2} = \dfrac{1!}{s^2}$ and $-\dfrac{48}{s^5} = -2\cdot\dfrac{4!}{s^5}$

So you have $\mathcal{L}^{-1}\left\{\dfrac{1}{s^2} - 2\cdot\dfrac{4!}{s^5}\right\} = \mathcal{L}^{-1}\left\{\dfrac{1}{s^2}\right\} - 2\mathcal{L}^{-1}\left\{\dfrac{4!}{s^5}\right\}$

From Table of Laplace Transform, you have $\mathcal{L}\{t^n\} = \dfrac{n!}{s^{n+1}}$ and hence $\mathcal{L}^{-1}\left\{\dfrac{n!}{s^{n+1}}\right\} = t^n$

So you have $\mathcal{L}^{-1}\left\{\dfrac{1}{s^2}\right\} - 2\mathcal{L}^{-1}\left\{\dfrac{4!}{s^5}\right\} = \boxed{t-2t^4}$ .

Hope this helps...

7 0

3 years ago

Given f(x)=2x-10 determine the value if f(x)=8

koban [17]

Answer:

f(x)=2x-10 ______(given)

f(x)=8 _______(given)

Therefore, according to the above problem

2x-10=8

2x=10+8

2x=18

x=18/2

<h3><u>9</u> is the right answer.</h3>

6 0

2 years ago

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