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2 years ago

12

To find the population of a city next year, we multiply its current population by 0.987. By what percent does the population dec

rease per year?

1 answer:

ololo11 [35]2 years ago

3 0

Answer:

$1.3\%$

Step-by-step explanation:

$1 - 0.987 = 0.013$

You might be interested in

4/9x + 1/5x =58 need help solving this

iogann1982 [59]

Answer:

x=90

Step-by-step explanation:

First, it would help to make it so that the x's are not next to fractions. To do this, you can multiply all terms in the equation by 45. 45 is the closest common factor of 9 and 5, the denominators of the fractions. The answer would be;

20x+9x=2610

Then solve.

29x=2610

x=90

6 0

3 years ago

Find the product of (2x-3) and (x+3)

miss Akunina [59]

Answer:

(2x - 3) * (x + 3)

=> (2x * x) + (-3 * 3)

=> 2x - 9

=> 2x -9

If my answer helped, kindly mark me as the brainliest!!

Thank You!!

3 0

2 years ago

The graph shows the relationship between mass and volume for pure silver. Use the graph to determine the density of pure silver

Natalija [7]

Answer:

C. Slope and $10.49 g/cm^3$

Step-by-step explanation:

We're missing the graph itself, but I can make an educated guess:

- Assuming x = volume and y = mass:

$p = \frac{m}{v}$

density = mass/volume

x = volume = run

y = mass = rise

mass/volume = rise/run = slope

The slope of the line (assuming the graph is purely linear) represents mass/volume, which is the formula for density.

I had to Google the density of silver itself. Do the math from the graph for a more appropriate answer, as the graph may be less scientifically precise.

7 0

3 years ago

Please please please help and solve this with steps, much help needed thank you :) 20 points for this!

leonid [27]

Answer:

$y=\sqrt{\frac{x^4-6x^2+12x+c_1}{2}},\:y=-\sqrt{\frac{x^4-6x^2+12x+c_1}{2}}$

(Please vote me Brainliest if this helped!)

Step-by-step explanation:

$\frac{dy}{dx}y=x^3+2x-5x+3$

$\mathrm{First\:order\:separable\:Ordinary\:Differential\:Equation}$

$\mathrm{A\:first\:order\:separable\:ODE\:has\:the\:form\:of}\:N\left(y\right)\cdot y'=M\left(x\right)$

1. $\mathrm{Substitute\quad }\frac{dy}{dx}\mathrm{\:with\:}y'\:$

$y'\:y=x^3+2x-5x+3$

2. $\mathrm{Rewrite\:in\:the\:form\:of\:a\:first\:order\:separable\:ODE}$

$yy'\:=x^3-3x+3$

$N\left(y\right)\cdot y'\:=M\left(x\right)$

$N\left(y\right)=y,\:\quad M\left(x\right)=x^3-3x+3$

3. $\mathrm{Solve\:}\:yy'\:=x^3-3x+3:\quad \frac{y^2}{2}=\frac{x^4}{4}-\frac{3x^2}{2}+3x+c_1$

4. $\mathrm{Isolate}\:y:\quad y=\sqrt{\frac{x^4-6x^2+12x+4c_1}{2}},\:y=-\sqrt{\frac{x^4-6x^2+12x+4c_1}{2}}$

5. $\mathrm{Simplify}$

$y=\sqrt{\frac{x^4-6x^2+12x+c_1}{2}},\:y=-\sqrt{\frac{x^4-6x^2+12x+c_1}{2}}$

7 0

3 years ago

Read 2 more answers

Which expressions are equivalent to -3(2+7) A: -6+21 or B:-21+6

Neporo4naja [7]

<u>Answer:</u>

None

<u>Explanation:</u>

-3(2+7) = -3×9 = -27

-6+21 = 15

-21+6 = -15

Hence there is no equivalence

3 0

2 years ago