Answer: 91.592
Step-by-step explanation:
Step-by-step explanation:
Hey there!!!
Here,
Given, A line passes through point (2,-2) and is perpendicular to the y= 5x+2.
The equation of a straight line passing through point is,

Now, put all values.

It is the 1st equation.
Another equation is;
y = 5x +2........(2nd equation).
Now, Comparing it with y = mx + c, we get;
m2=5
As per the condition of perpendicular lines,
m1×m2= -1
m1 × 5 = -1
Therefore, m2= -1/5.
Keeping the value of m1 in 1st equation.

Simplify them.



Therefore the required equation is x+5y+8= 0.
<em><u>Hope it helps</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em>
Answer:
The Y intercept is -5 and the slope is -5/2
Answer:
A=SqRt(c^2-b^2)
Step-by-step explanation:
a^2 + b^2 = c^2
rearrange to solve for a^2
a^2= c^2-b^2
take the square root of each side
a= square root (c^2-b^2)