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Lilit [14]
4 years ago
15

For each of the sequences below, enter either diverges if the sequence diverges, or the limit of the sequence if the sequence co

nverges as n -------> [infinity].
A. 5/n + n/5
B. 5^-n
C. Sin n/5n
D. 5n + 5/n
Mathematics
1 answer:
Tanzania [10]4 years ago
5 0

Answer:

As n tends to positive infinity, we have that,

A. 5/n + n/5 ---- converges

B. 5^-n. -----------converges

C. Sin n/5n------ converges

D. 5n + 5/n ------diverges

Step-by-step explanation:

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it is point G

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3 years ago
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melisa1 [442]

Answer:

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Step-by-step explanation:

3 0
3 years ago
(50 points and brainliest) y=x^3-2x^2+25x-50
lesya [120]

Answer: 2x to the second power+25x−50

Step-by-step explanation:  

2x to the second power+25x−50

There are no like terms.

6 0
3 years ago
Find all rational polynomials p(x) = x3 + ax2 + bx + c such that a, b, c are
Naddik [55]

Answer:

  • p(x) = x³ +0x² +0x +0
  • p(x) = x³ +x² -x -1
  • p(x) = x³ -x² -2x

Step-by-step explanation:

If the roots of p(x) are a, b, c, then it factors as ...

  p(x) = (x -a)(x -b)(x -c)

and the expanded form is ...

  p(x) = x^3 -(a+b+c)x^2 +(ac +b(a+c))x -abc

The requirement that the coefficients match the roots means we have three equations in three unknowns:

  a = -(a+b+c)

  b = ac +b(a+c)

  c = -abc

The attachment shows the solutions to these equations. The solutions are found by making the substitutions ...

  • b = x
  • c = y
  • a = -(x+y)/2

This leaves us with two equations in two unknowns that can be graphed on a Cartesian plane. The graph of the second equation is a circle:

  x(1 -a -y) -ay = 0   ⇒   (x +1)^2 +y^2 = 1

The graph of the first equation is the union of the line y=0 and two hyperbolas. The points of intersection between this graph and the circle are ...

  (x, y) = (-2, 0), (-1, -1), (0, 0)   ⇒   (a, b, c) = (1, -2, 0), (1, -1, -1), (0, 0, 0)

The three polynomials that correspond to these values are shown above and in the attachment.

_____

<em>Additional comment</em>

There is an irrational fourth solution to the requirement that the roots match the coefficients.

8 0
3 years ago
If you bike 8 miles south and then 6 miles east, what is the distance you are from your starting point? 10 miles 100 miles 14 mi
Andreyy89

Answer:

10 miles

Step-by-step explanation:

Given: Bike goes 8 miles south and then 6 miles east

To find: distance between the final point and the starting point

Solution:

<u>Pythagoras Theorem</u>

In a right angled triangle, square of hypotenuse is equal to the sum of squares of the two sides.

In ΔOAB,

OB^2=OA^2+AB^2

Put OA=8\,,\,AB=6

OB^2=8^2+6^2=64+36=100

Take square root on both sides.

OB=\sqrt{100}=10\,\,miles

So, distance between the final point and the starting point is 10 miles

Download pptx
5 0
3 years ago
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