Answer:
a = 6, b = 8, and c = 10.
Step-by-step explanation:
You can easily use the Pythagorean Theorem to solve all of these.
a = 4; b = 6; c = 8... 4^2 + 6^2 = 16 + 36 = 52. 8^2 = 64. 52 is not equal to 64, so the first choice is not a right triangle.
a = 6; b = 8; c = 10... Well this is a multiple of the 3-4-5 Pythagorean triple, so this is a right triangle.
a = 5; b = 6; c = 761... 5^2 + 6^2 = 25 + 36 = 61. 761^2 = 579121, which is not equal to 61, so the third choice is not a right triangle.
a = 6; b = 9; c = 12... 6^2 + 9^2 = 36 + 81 = 117. 12^2 = 144, which is not equal to 117, so the fourth choice is not a right triangle.
The only case where there is a right triangle is the second choice, where a = 6, b = 8, and c = 10.
Hope this helps!
Answer:
a. x² + 10x + 25
Step-by-step explanation:
because
(x + 5)² = (x + 5)(x + 5) = x² + 5x + 5x + 25 = x² + 10x + 25
so, it is a perfect square of (x + 5).
Since the function is h(t) = −5t² + 15t, the domain of the function h(t) is 0 ≤ t ≤ 3
<h3>What is the domain of a function?</h3>
The domain of a function is the range of input values that make the function have real values.
Now given the function h(t) = −5t² + 15t, it will have real values when
h(t) ≥ 0
So, h(t) ≥ 0
⇒ −5t² + 15t ≥ 0
Factorizing, we have
-5t(t - 3) ≥ 0
5t(t - 3) ≤ 0
t(t - 3) ≤ 0
t ≤ 0 and t - 3 ≤ 0
t ≤ 0 and t ≤ 3
For t ≤ 0, say -1, t(t - 3) = -1(-1 - 3) = -1(-4) = 4 ≥ 0
For 0 ≤ t ≤ 3, say 2, t(t - 3) = 2(2 - 3) = 2(-1) = -2 ≤ 0
For t ≥ 3, say 4, t(t - 3) = 4(4 - 3) = 4(1) = 4 ≥ 0
Since we require t(t - 3) ≤ 0, the domain of t is thus 0 ≤ t ≤ 3
So, the domain of the function h(t) is 0 ≤ t ≤ 3
Learn more about domain of a function here:
brainly.com/question/204418
#SPJ1
The area of a circle by definition is given by:
A = pi * r ^ 2
Where,
r: radius
Substituting the values we have:
A = (3.14) * (15) ^ 2
A = 706.5 mm ^ 2
Answer:
The approximate area of the compass is:
A = 706.5 mm ^ 2
