DE is parallel to AC. Find the lengths of AC and AD. FAST!!!
2 answers:
Answer:
we have:
∆BDE is similar to ∆BAC
so their side are proportional :
BD/BD=BE/BC
2/BD=4/(6+4)
BD=2×10/4
BD=5
again
BE/BC=DE/AC
4/10=5/AC
AC=5×10/4
AC=25/2
Now,
<u>AC</u><u>=</u><u>2</u><u>5</u><u>/</u><u>2</u><u> </u><u>or</u><u> </u><u>1</u><u>2</u><u>.</u><u>5</u><u>.</u>
<u>AD</u><u>=</u><u>BA-BD</u><u>=</u><u>5</u><u>-</u><u>2</u><u>=</u><u>3</u><u>.</u>
<u>is</u><u> </u><u>your</u><u> </u><u>answer</u><u>.</u>
Answer:
AC = 12.5, AD = 3
Step-by-step explanation:
A line parallel to a side of a triangle and intersecting the other 2 sides, divides those sides proportionally, that is
=
, substitute values
=
( cross- multiply )
4 AD = 12 ( divide both sides by 4 )
AD = 3
-----------------------------------------
Δ BDE and Δ BAC are similar, so the ratios of corresponding sides are equal, that is
=
, substitute values
=
( cross- multiply )
2 AC = 25 ( divide oth sides by 2 )
AC = 12.5
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Answer:
4269
———— = 21.34500
200
Step-by-step explanation:
Step 1 :
4269
Simplify ————
50
Equation at the end of step 1 :
4269
———— ÷ 4
50
Step 2 :
4269
Divide ———— by 4
50
Final result :
4269
———— = 21.34500
200
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Answer:
x=5°, angle A=50°
Step-by-step explanation:
8x+11x-5+90=180
19x=95
x=5°
-->A= 11x-5
= 11*5-5
=50°
3(1) - 8 = 3 - 8 = -5
just plug in 1 for x that's what f(1) means
It is already in identity.
cos (x - y) - cos (x + y) = 2 sin(x) sin (y)