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Natasha_Volkova [10]
3 years ago
15

Evaluate Tan^-1 1 Easy points !!

Mathematics
1 answer:
Allisa [31]3 years ago
6 0

easy points yes please

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Sophia had 64¢ until she spent 1 quarter. How much money does Sophia have now?
aleksklad [387]

Answer:

Sophia now has 39 cents.

Step-by-step explanation:

One quarter = 25 cents

Since Sophia had 64 cents until she spent 25 cents (1 quarter).

So we subtract 25 cents from 64 cents.

\:  \:  \: 64 \: cents \\  \frac{ - 25 \: cents}{ \:  \:  \: 39 \: cents}

Therefore, Sophia now has 39 cents.

7 0
3 years ago
Simplify the sum (complex fraction)
andrey2020 [161]
I got 2d^4-2d^2-5/d^2

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3 years ago
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What is the sum of a geometric sequence 1, 3, 9, ... if there are 12 terms?
attashe74 [19]
We know that
a1=1
a2=3
a3=9
a2/a1=3/1----> 3
a3/a2=9/3----> 3
<span>common ration r is equal to 3
number of terms n  is 12

The </span><span>Sum of geometric series is given by the formula
</span>Sum=a1*[1-r<span>^n]/[1-r]
</span>Sum=1*[1-3^12]/[1-3]-----> Sum=[1-3^12]/[1-3]----> [3^12-1]/[3-1]
<span>Sum=531440/2-----> 265720

the answer is
265720



</span>
4 0
3 years ago
I need help with 9-81 ASAP PLS THIS IS MY HW
Yuri [45]
It is -72 lol. that's pretty basic you know
4 0
3 years ago
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Write the slope-intercept form of the equation of the line described.
Ad libitum [116K]

                                                  7)

Given the line

y=-x+2

We know that the slope-intercept form of the line equation is

y=mx+b

here

m is the slope and b is the intercept

Thus, the slope = -1

We know that the parallel lines have the same. Thus, the slope of the parallel line is: -1

Using point-slope of the line equation

y-y_1=m\left(x-x_1\right)

substituting the values m = -1 and the point (4, 0)

y-0 = -1 (x-4)

Writing in the slope-intercept form

y = -x+4

Thus, the slope-intercept form of the equation of the line equation parallel to y=-x+ 2 will be:

  • y = -x+4

                                                      8)

<em>Note: </em><em>Your line is a little bit unclear. But, I am assuming the</em>

<em>ine is: </em>y = -x-1

<em />

Given the assumed line

y = -x-1

We know that the slope-intercept form of the line equation is

y=mx+b

here

m is the slope and b is the intercept

Thus, the slope = m = -1

We know that a line perpendicular to another line contains a slope that is the negative reciprocal of the slope of the other line, such as:

slope = m = -1

perpendicular slope = – 1/m = -1/-1 = 1

Using point-slope of the line equation

y-y_1=m\left(x-x_1\right)

substituting the values m = 1 and the point (4, 3)

y - 3 = 1 (x-4)

Writing in the slope-intercept form

y-3 = x-4

y = x-4+3

y = x - 1

Thus, the slope-intercept form of the equation of the line equation perpendicular to y = -x-1 will be:

  • y = x - 1

5 0
2 years ago
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