Evaluate Tan^-1 1<br> Easy points !!

he ratio of your monthly allowance to your friend’s monthly allowance is 5 : 3. Both of your monthly allowances total $40. How m

Elena-2011 [213]

Answer:

your allowance is $25 and your friends is $15

Step-by-step explanation:

40/8*3=15

40/8*5=25

6 0

2 years ago

Read 2 more answers

The graph of f(x) = x^2 has been shifted into the form f(x) = (x − h)^2 + k

stepan [7]

$\bf \qquad \qquad \qquad \qquad \textit{function transformations}
\\ \quad \\\\
% left side templates
\begin{array}{llll}
f(x)=&{{ A}}({{ B}}x+{{ C}})+{{ D}}
\\ \quad \\
y=&{{ A}}({{ B}}x+{{ C}})+{{ D}}
\\ \quad \\
f(x)=&{{ A}}\sqrt{{{ B}}x+{{ C}}}+{{ D}}
\\ \quad \\
f(x)=&{{ A}}(\mathbb{R})^{{{ B}}x+{{ C}}}+{{ D}}
\\ \quad \\
f(x)=&{{ A}} sin\left({{ B }}x+{{ C}} \right)+{{ D}}
\end{array}\\\\
--------------------\\\\$

$\bf \bullet \textit{ stretches or shrinks horizontally by } {{ A}}\cdot {{ B}}\\\\
\bullet \textit{ flips it upside-down if }{{ A}}\textit{ is negative}\\
\left. \qquad \right. \textit{reflection over the x-axis}
\\\\
\bullet \textit{ flips it sideways if }{{ B}}\textit{ is negative}\\
\left. \qquad \right. \textit{reflection over the y-axis}$

$\bf \bullet \textit{ horizontal shift by }\frac{{{ C}}}{{{ B}}}\\
\left. \qquad \right. if\ \frac{{{ C}}}{{{ B}}}\textit{ is negative, to the right}\\\\
\left. \qquad \right. if\ \frac{{{ C}}}{{{ B}}}\textit{ is positive, to the left}\\\\
\bullet \textit{ vertical shift by }{{ D}}\\
\left. \qquad \right. if\ {{ D}}\textit{ is negative, downwards}\\\\
\left. \qquad \right. if\ {{ D}}\textit{ is positive, upwards}\\\\
\bullet \textit{ period of }\frac{2\pi }{{{ B}}}$

with that template in mind, let's see, it went to the right 2 units, and then up 3 units.

that simply means, C = -2, D = 3.

8 0

2 years ago

If 8n+22=70 find the value of 3n

kondaur [170]

8n + 22 = 70

-22 -22

8n = 48
n = 48/8

n = 6

n*3 = 3n = 6*3 = 18

3n = 18

6 0

3 years ago

Read 2 more answers

Find the amplitude and the equation of the midline of the periodic function.

Masja [62]

Answer:

Option B. Amplitude =3 midline is y =2.

Step-by-step explanation:

In the graph attached we have to find the amplitude and midline of the periodic function.

Amplitude of the periodic function = (Distance between two extreme points on y asxis)/2

= (5-(-1))/2 = (5+1)/2 =6/2 =3.

Since amplitude of this function is 3 and by definition amplitude of any periodic function is the distance between the midline and the extreme point of wave on one side.

Therefore midline of the wave function is y=2 from which measurement of the amplitude is 3.

6 0

2 years ago

Read 2 more answers

Find the midpoint from (-2,-2) to (6,6)

timama [110]

(2,2)

(x1+x2)/2, (y1-y2)/2
(-2+6)/2=(2)
(-2+6)/2=2

4 0

2 years ago

Read 2 more answers

Evaluate Tan^-1 1 Easy points !!