Which quadratic function in vertex form has a vertex at (−5 , −4) and passes through the point (−2 , −1)?
1 answer:
Answer:
y = 1/3(x + 5)^2 - 4
Step-by-step explanation:
The general vertex form is;
y = a(x-h)^2 + k
From the question, (h,k) are the coordinates of the vertex which is (-5,-4)
So we have
y = a(x + 5)^2 -4
So we need to get the leading coefficient
Simply substitute the point it passes through
x = -2 and y = -1
-1 = a(-2 + 5)^2 - 4
-1 = a(3)^2 -4
-1 = 9a -4
9a = 4-1
9a = 3
a = 3/9
a = 1/3
So the equation is;
y = 1/3(x + 5)^2 - 4
You might be interested in
Answer:
x=1
Step-by-step explanation:
3x=4-1
3x=3
x=1
Answer:
k= m/7
Step-by-step explanation:
Answer:
that's good12 pages=1hour 6 pages= 30 min
I believe the answer would be 10:20 am.
Answer: 6, 5
Step-by-step explanation: