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sp2606 [1]
3 years ago
15

B to the eighth power multiplied by b to the fourth power

Mathematics
1 answer:
scZoUnD [109]3 years ago
7 0
U just add the exponents.

b^8 x b^4 = b^12

hope this helps :)





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A school pays $1,825 for 150 shirts. This includes the $25 flat-rate shipping cost. What equation models the total cost as a fun
likoan [24]

Answer:

c(t) = 25 +12 * t

where t is the number of shirts

Step-by-step explanation:

The total cost for the shirts  is the flat fee plus the cost per shirt times 150 shirts

total = fee + cost per shirt* shirts

1825 = 25 +c*150  

 where c is the cost per shirt

We need to determine the cost per shirt by subtracting 25 from each side

1825-25 = 150c

1800 =150c

Divide by 150 on each side

1800/150 =150c/150

12 =c

Each shirt costs 12 dollars

We want to make the function in terms of cost per shirt

c(t) = 25 +12 * t

where t is the number of shirts

6 0
3 years ago
Which is equivalent sin^-1 (cos(pi/2))?Give your answer in radians
NNADVOKAT [17]

Answer:

Given the expression: \sin^{-1}(\cos(\frac{\pi}{2}))

Let the value of the given expression in radians be \theta

then;

\sin^{-1}(\cos(\frac{\pi}{2})) =\theta

\cos \frac{\pi}{2} = \sin \theta              ......[1]

We know the value of \cos \frac{\pi}{2} = 0

Substitute the given value in [1] we have;

\sin \theta = 0

Since, the value of \sin \theta is 0, therefore, the value of \theta is in the form of:

\theta = n\pi ; where n is the integer.

At n =0, 1 and 2, {Since, n is the integer}

Value of  \theta =0, \pi and 2\pi

therefore, the answer in radians either   0 , \pi or 2\pi


6 0
3 years ago
Read 2 more answers
The following table shows the number of feet a bird flies above the ground as a function of time: (In the picture)
Otrada [13]

Answer:

  D.)  (14, 0); the time it takes for the bird to reach the ground

Step-by-step explanation:

The attached graph shows a plot of the table values and the two offered solution options.

The dependent variable in this scenario is the bird's height above the ground. When that is zero, the bird is on the ground. This fact makes choices B and C seem ridiculous.

We note from the table and graph that the bird is on a path that decreases in height by 3 feet every 2 seconds. If the bird continues that rate of descent, it will reach the ground after 14 seconds.

That is, its (time, height) pair will be (14, 0), matching choice D.

_____

Choosing any answer to this question requires making assumptions that are inconsistent with real-world bird behavior. At least, the problem statement should say what assumptions are applicable.

4 0
3 years ago
Read 2 more answers
part 2. Find the value of the trig function indicated, use for that Pythagorean theorem to find the third side if you need it.​
andreev551 [17]

Answer:  \bold{5)\ \cos \theta=\dfrac{\sqrt{11}}{6}\qquad 6)\ \tan \theta =\dfrac{8}{17}\qquad 7)\ \cos \theta = \dfrac{4}{3}\qquad 8)\ \cos \theta = \dfrac{\sqrt{10}}{10}}

<u>Step-by-Step Explanation:</u>

Pythagorean Theorem is: a² + b² = c²  , <em>where "c" is the hypotenuse</em>

5)\ \cos \theta=\dfrac{\text{side adjacent to}\ \theta}{\text{hypotenuse of triangle}}=\dfrac{3\sqrt{11}}{18}\quad \rightarrow \large\boxed{\dfrac{\sqrt{11}}{6}}

Note: (15)² + (3√11)² = hypotenuse²   →   hypotenuse = 18

6)\ \cos \theta=\dfrac{\text{side adjacent to}\ \theta}{\text{hypotenuse of triangle}}=\dfrac{8}{17}\quad =\large\boxed{\dfrac{8}{17}}

Note: 8² + 15² = hypotenuse²   →   hypotenuse = 17

7)\ \tan \theta=\dfrac{\text{side opposite to}\ \theta}{\text{side adjacent to}\ \theta}=\dfrac{20}{15}\quad \rightarrow \large\boxed{\dfrac{4}{3}}

Note: hypotenuse not needed for tan

8)\ \cos \theta=\dfrac{\text{side adjacent to}\ \theta}{\text{hypotenuse of triangle}}=\dfrac{2}{2\sqrt{10}}\quad =\large\boxed{\dfrac{\sqrt{10}}{10}}

Note: 2² + 6² = hypotenuse²   →   hypotenuse = 2√10

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2 years ago
during the 2011 season, a quarterback passed for 302 yards per game. he played in all 16 regular season games that year. how man
MariettaO [177]
302 times 16 because he passed 302 yards for every game 4832
7 0
3 years ago
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