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3 years ago

What are the effects of moon rotation and revolution

Physics

1 answer:

polet [3.4K]3 years ago

7 0

Answer:

The effects of the Moon's rotation includes;

1) The Moon rotation and revolution gives the appearance of a perfectly still Moon to observers of the Moon from the Earth

2) The Moon has two sides, the near side that continuously faces the Earth and the "back" or far side, which is also known as the dark side of the Moon

The effect of the Moon's revolution

1) The tides in the ocean and water bodies, due to the gravitational forces from the Moon

2) The changes in the observed shape of the Moon due to the amount of Sunlight that is able to be reflected from the Moon as a result of the relative position of the Moon, the Earth and the Sun, at a given point in time

3) Lunar and Solar eclipse, when the Earth and the Moon blocks the light coming from the Sun respectively, due to their combined revolution

Explanation:

The duration of the Moon's orbit round the Earth = 27.322 days

The time it takes the Moon to rotate round its axis = 27 days

The Moon is the closest cosmic body to the Earth.

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The mass of Tesla Model S is 2000 kg and its engine produces

yulyashka [42]

Answer:

The ratio of the power generated by the engines are $\dfrac{2}{3}$

(b) is correct option.

Explanation:

Given that,

Mass of Tesla = 2000 Kg

Torque = 400 Nm

Mass of Mercedes = 1.5 M Tesla

The Benz engine produces 50% more torque than the Tesla.

We need to calculate the power generated by the engines 6 seconds after a start from rest

Using formula of power

$P=F\cdot v$

We know that,

$v=at$

$v=\dfrac{F}{m}t$

$v=\dfrac{\tau}{mr}t$

Put the value of F and v in equation (I)

$P=\dfrac{\tau}{r}\times\dfrac{\tau}{mr}t$

$P=\dfrac{\tau^2t}{mr^2}$

Here, r and t are same for both bodies.

$P\propto\dfrac{\tau^2}{m}$

We need to calculate the ratio of the power generated by the engines

Using formula of power

$\dfrac{P_{T}}{P_{B}}=\dfrac{\tau_{T}^2}{m_{T}}\times\dfrac{m_{B}}{\tau_{B}}$

Put the value into the formula

$\dfrac{P_{T}}{P_{B}}=\dfrac{400^2}{2000}\times\dfrac{3000}{600^2}$

$\dfrac{P_{T}}{P_{B}}=\dfrac{2}{3}$

Hence, The ratio of the power generated by the engines are $\dfrac{2}{3}$

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3 years ago

You were in a tog-o-war contest which your team won. Write a letter to your friend that tells why your team won the contest. Rem

ollegr [7]

Answer:

Imagine a tug-of-war between you and one

friend. If you are stronger, you apply more

force to the rope. You pull your friend across

the line, and you are the winner! If your friend

is stronger, he might pull you across the line.

Sometimes the forces are equal. Neither you

nor your friend moves across the line. The two

forces are balanced.

We say that the net force on an object is the combination of all the forces acting on it. To find the net force of

forces that are acting in the same direction, add them together. For example, if you pull on a box with a force of 25

newtons (N) while your friend pushes the box (in the same direction you are pulling) with a force of 30 N, the net

force applied to the box in that direction is 55 newtons.

To find the net force of forces that are acting in opposite directions, subtract the smaller force from the larger

one. If you are pulling on a tug-of-war rope with a force of 40 N, and your friend is pulling with a force of 35 N in

the opposite direction, the net force on the rope is 5 newtons in your direction. You win!

Explanation:

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3 years ago

In Robin’s linguistics class, the teacher and students are discussing how the word “nice” once meant “foolish” and how “awful” u

aleksklad [387]

The answer would be B.

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Hope this helped!

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3 years ago

Read 2 more answers

The mass of the sphere is 0.151 kg. What is the rotational inertia of the wheel

shusha [124]

Complete Question:

The mass of the sphere is 0.151 kg. What is the rotational inertia of the wheel? Recall that the radius of the sphere is about 0.312 m. Express your answer with three significant figures in Kg.m².

Answer:

I = 5.88*10⁻³ kg.m²

Explanation:

It can be showed that the rotational inertia (or moment of inertia) for a solid sphere of radius r and mass m, regarding any axis passing through the center of the sphere, can be expressed as follows:

I = (2/5)*m*r² (1)

where m= 0.151 kg, and r =0.312 m. (Our givens).

Replacing in (1) we have:

I = (2/5)*0.151 kg*(0.312m)² = 5.88*10⁻³ kg.m²

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Answer:

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3 years ago

What are the effects of moon rotation and revolution​

What are the effects of moon rotation and revolution