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DIA [1.3K]
3 years ago
5

Un coche de unos 500 kg viaja a 90 km/h. Percibe un obstáculo y debe frenar a tope. Por las marcas del suelo se sabe que el espa

cio de frenada fue de 125 m. ¿Cuánto valía la fuerza de rozamiento entre el coche y la carretera?
Physics
1 answer:
a_sh-v [17]3 years ago
3 0

Answer:

THERE'S A GIRL WHO WILL STEAL YOUR INFO, PLZ DON"T PRESS THE LINK IF SHE ASKS YOU TOO!!!!!

Explanation:

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A rock of mass 0.340 kg is spun horizontally at the end of a wire that has a diameter of 1.00 mm. If the wire gets stretched by
borishaifa [10]

Answer:

Y = 78.13 x 10⁹ Pa = 78.13 GPa

Explanation:

First we will find the centripetal force acting on the wire as follows:

F = mv²/r

where,

F = Force = ?

m = mass of rock = 0.34 kg

v = speed = 19 m/s

r = length of wire

Therefore,

F = (0.34)(19)²/r

F = 122.74/r  

now, we find cross-sectional area of wire:

A = πd²/4

where,

A = Area = ?

d = diameter of wire = 1 mm = 0.001 m

Therefore,

A = π(0.001)²/4

A = 7.85 x 10⁻⁷ m²

Now, we calculate the stress on wire:

Stress = F/A

Stress = (122.74/r)/(7.85 x 10⁻⁷)

Stress = 1.56 x 10⁸/r

Now, we calculate strain:

Strain = Δr/r

where,

Δr = stretch in length = 2 mm = 0.002 m

Therefore,

Strain = 0.002/r

now, for Young's modulus (Y):

Y = Stress/Strain

Y = (1.56 x 10⁸/r)/(0.002/r)

<u>Y = 78.13 x 10⁹ Pa = 78.13 GPa</u>

8 0
3 years ago
4. A truck with a mass of 6,500 Kg can exert a force of 29,250 N when stopping. What is the deceleration
Vitek1552 [10]
Deceleration = 29250 / 6500 = 4.5 m/s^2
7 0
4 years ago
How much heat is required to convert 10.0 g of ice at -14.0 ∘c to steam at 100.0 ∘c?
sdas [7]
What do you think? how long does your hand touch fire until it feels heat.


4 0
3 years ago
There are two processes - let us call them P and Q. The similarity between P and Q is that both represent a change from liquid s
Komok [63]
P and Q are evaporation and boiling.
7 0
2 years ago
Two billion people jump up in the air at the same time with an average velocity of 7.0 m/sec. If the mass of an average person i
faust18 [17]

Well first of all, you must realize that it depends on how the jumpers are distributed on the earth's surface.  If,say, one billion of them are in the eastern  hemisphere and the other billion are in the western one, then the sum of all of their momenta could easily be zero, and have no effect at all on the planet.  I'm pretty sure what you must have in mind is to consider the Earth to be a block, with a flat upper surface, and all the people jump in the same direction.

average mass per person = 60 kg.
jump velocity = 7 m/s straight up and away from the block, all in the same direction
one person's worth of momentum = (m) (v) = 420 kg.m/s
sum of two billion of them = 8.4 x 10¹¹ kg-m/s all in the same direction

Earth's "recoil" momentum = 8.4 x 10¹¹ in the opposite direction = (m) (v)

Divide each side by 'm' :     v = (momentum) / (mass) =

The Earth's "recoil" velocity is   (8.4 x 10¹¹) / (5.98 x 10²⁴) = 

                                                               1.405 x 10⁻¹³ m/s =

                                              <em> 0.00000000014 millimeter per second

</em>
I have no intuitive feeling for this kind of thing, so can't judge whether
the answer is reasonable.  But my math and physics felt OK on the
way to the solution, so that's my answer and I'm sticking to it.

4 0
4 years ago
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